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4(q+3) + 3q = -30
4q +12 + 3q = -30
7q+12= -30
7q = -12-30
7q = -42
q = -6
p = -3
4q +12 + 3q = -30
7q+12= -30
7q = -12-30
7q = -42
q = -6
p = -3
Answer:
Step-by-step explanation:
Translation of a point (h, k) by 'a' units to the right and 'b' units upwards is defined by,
(h, k) → (h + a, k +b)
Coordinates of A → (-4, -2)
Coordinates of B → (1, -1)
Coordinates of C → (0, -5)
If these points are shifted 4 units right and 3 units up,
By applying rules of the translation,
Coordinates of image point A' → (-4 + 4, -2 + 3)
→ (0, 1)
Coordinates of B' → (1 + 4, -1 + 3)
→ (5, 2)
Coordinates of C' → (0 + 4, -5 + 3)
→ (4, -2)
Now plot these points on the graph.
