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iogann1982 [59]
3 years ago
15

Express as a trinomial. (x + 4)(x - 1)

Mathematics
1 answer:
katovenus [111]3 years ago
8 0

Answer:

x^2+3x−4

Step-by-step explanation:

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WILL VOTE BRAINLIEST TO THE FIRST CORRECT ANSWER
KonstantinChe [14]

Answer:

D

Step-by-step explanation:

The D answer choice is the correct functions needed to create the pictured graph, I have pictured these functions in a graphing calculator below

7 0
1 year ago
19. Heather invests $4,900 in an account with a 3.5% interest rate, making no other deposits or withdrawals. What will Heather’s
denis-greek [22]

Answer:

\$5,828.28

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=5\ years\\ P=\$4,900\\ r=0.035\\n=2  

substitute in the formula above  

A=\$4,900(1+\frac{0.035}{2})^{2*5}  

A=\$4,900(1.0175)^{10}=\$5,828.28

5 0
3 years ago
Pls pls pls pls pls help
raketka [301]

Answer:38x-34

Step-by-step explanation:

f(x)=x^2+3x-7

g(x)=5x-3

We multiply the entire F equation times two, (x^2+3x-7)*4=

(4x^2+12x-28)

Now the entire g equation by 2, (5x-3)*2

(10x-6)

Now we add both equation

(4x^2+12x-28)+(10x-6)

(4x^2+22x-34)

(4x*4x+22x-34)

(16x+22x-34)

38x-34

Hopefully this is correct :)))

7 0
3 years ago
last year, emilia went bowling several times and earned an average score of 100 points. this year, after taking a class at schoo
MrRissso [65]
198 is the answer I think
6 0
3 years ago
The equation 12x² + 4kx + 3 = 0 has real and equal roots, if
sleet_krkn [62]

Answer:

k=\pm3

Step-by-step explanation:

[...] if you can write the LHS as a perfect square, or if you can't spot a factorization of it right away, if and only if the discriminant \Delta = b^2-4ac (or, if b is an even number, 1/4 of it) is zero.

<u>I see it! I see it!</u>

Stare at it for a while. First term is 3(2x)^2, third term is 3(1)^2, we are missing a double product, but we can play with k. For the LHS to be 3(2x\pm1)^2 = 3(4x^2\pm4x+1) = 12x^2\pm12x+3 you just need 4k= \pm12 \rightarrow k=\pm3.

<u>I don't see it...</u>

Then number crunching it is. Set the discriminant to 0, solve for k

\frac{\Delta}4 = 4k^2-12\cdot 3 =0 \rightarrow 4k^2=36 \\k^2 = 9 \rightarrow k=\pm3

8 0
2 years ago
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