n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
Collin
22 years = 55,000 USD
+15 years
37 years = 2 x 55,000 = 110,000 USD
+15 years
52 years = 2 x 110,000 = 220,000 USD
Cameron
22 years = 35,000 USD
+10 years
32 years = 2 x 35,000 = 70,000 USD
+10 years
42 years = 2 x 70,000 = 140,000 USD
+10 years
52 years = 2 x 140,000 = 280,000 USD
+10 years
62 years = 2 x 280,000 = 560,000 USD
Retirement Salaries
Collin = 220,000 USD
Cameron = 560,000 USD
Answer:
The smaller number is 127
Step-by-step explanation:
Lets write the given problem in equation form
sum of consecutive numbers n and n + 1 = n + n + 1 = 2n + 1
now we find twice of the sum of consecutive numbers n and n + 1
2*(2n + 1) = 4n + 2
given that
twice the sum of consecutive numbers n and n + 1 is 510
thus,
4n + 2 = 510
=> 4n = 510 -2 = 508
=> n = 508/4 = 127
Thus, the numbers are n = 127
n+1 = 127 + 1 = 128
the smaller number is 127
6/8 *3/2.
6*3=18. /8*2=16
18/16
Divide top and bottom by 2
9/8
First solve your inequality step by step.
y+15<3
= y<-12
Answer is A. y<-12
Answer will help you.
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