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kow [346]
3 years ago
9

In the graph y = x + 3

Mathematics
2 answers:
masya89 [10]3 years ago
6 0

Answer:

Its equal 3

Step-by-step explanation:

because x+3 = 3 because x is 0 so that means that 0+3=3 so y is 3 trust me

vladimir2022 [97]3 years ago
6 0

Answer:

let y =3

then y= x+3

3= x+3

3-3 =x

x =0 at x = 0 the value of y = 3

let x = -3

y = x +3

y = -3+3

y= o

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3x +2x-5+(-7x+8)=

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Step-by-step explanation:

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3 years ago
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A company paid $48 for 2 cases of printer paper. Each case contained 12 packages of paper. Next month the company’s office manag
Studentka2010 [4]

Answer:

$360.

Step-by-step explanation:

First we need to find how much it costs for a single case of printer paper.

48 ÷ 2 = 24

It costs $24 to buy one case of 12 packages.

Now we have to figure out how many cases we will need to buy for the total amount of 180 packages.

I will divide 12 from 180.

180/12 = 15.

You will need to buy 15 cases to get 180 packages.

Now to find the cost, we have to multiply.

x = 15 (amount of cases)

y = $24 (price of case)

z = How much it costs.

x * y=z

Substitute:

15*24=z

Multiply:

15 * 24= 360

z=360

If the price does not change, the total cost of next month's order will be $360.

6 0
3 years ago
Mario is making dinner for 9 people. Mario buys 6 containers of soup. Each container is 18 ounces. If everyone gets the same amo
fiasKO [112]
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3 0
3 years ago
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Step-by-step explanation:

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5 0
3 years ago
Given that W is directly proportional to the square of V, and W = 320 when V = 8, find W when V = 9.
lorasvet [3.4K]

The value of W when V = 9 is 405

<h3>How to solve for W?</h3>

The variation is a direct variation from W to V^2.

This means that:

W = kV^2

Where k is the constant of variation.

W = 320 when V = 8 means that:

320 = k * 8^2

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320 = 64k

Divide both sides by 64

k = 5

Substitute k = 5 in W = kV^2

W = 5V^2

When V = 9, we have:

W = 5 * 9^2

Evaluate

W = 405

Hence, the value of W when V = 9 is 405

Read more about direct variation at:

brainly.com/question/6499629

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3 0
2 years ago
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