All categories

3 years ago

Please help me solve this please

Mathematics

1 answer:

g100num [7]3 years ago

5 0

Step-by-step explanation:

You might be interested in

Select the correct answer from the drop-down menu. And the surface area of this triangular prism. 2 in. 10 in. 6 in. 2 in. 8 in.

seraphim [82]

Answer:

Step-by-step explanation:

i just did math and got it correct

6 0

3 years ago

7/5 + 2/3 - 1 = ayuda porfa

brilliants [131]

Answer:

$1\frac{1}{15}$

Step-by-step explanation:

$\frac{7}{5}+\frac{2}{3}-1\\$

Convertir elemento a fracción: 1 = 1/1

$=-\frac{1}{1}+\frac{7}{5}+\frac{2}{3}$

Mínimo común múltiplo de 1,5,3 = 15

Ajustar fracciones según el mcm

$=-\frac{15}{15}+\frac{21}{15}+\frac{10}{15}$

Dado que los denominadores son iguales, combine las fracciones:

$\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\\\= \frac{-15+21+10}{15}\\\\$

Sumar Restar los números: -15 + 21 + 10 = 16

$=\frac{16}{15}\\\\16\div 15 = 1 \: remainder 1\\\\=1\frac{1}{15}$

4 0

3 years ago

Step 1: For each circle (A-G) in the table below, use the given information to determine the missing

Sergio039 [100]

Answer:

I don't really understand the question

Step-by-step explanation:

3 0

3 years ago

General solution for cos(5x)-cos(2x)=0

Irina-Kira [14]

<span>Simplifying cos(5x) + cos(2x) = 0
(5x) cos * 5x + cos(2x) = 0
</span> 5cos * x + cos(2x) = 0 Multiply cos * x 5cosx + cos(2x) = 0
(2x) 5cosx + cos * 2x = 0
5cosx + 2cos * x = 0 Multiply cos * x 5cosx + 2cosx = 0 5cosx + 2cosx = 7cosx 7cosx = 0 Solving 7cosx = 0 Solving for variable 'c'. cosx = 0 Simplifying cosx = 0

Hope this helps!

In short your answer is 0

7 0

4 years ago

NEED HELP ASAP WILL GIVE BRAINLIEST!!! i just need the picture drawn correctly pls before 12pm tmr. offering 100 points and brai

Ivan

Answer:

The opposite of 12 is -12.

Step-by-step explanation:

-12, -11, -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12

All you have to do is do the negative version of that same original number.

8 0

3 years ago