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3 years ago

(I WILL GIVE BRAINLIEST)

Mathematics

2 answers:

Nezavi [6.7K]3 years ago

3 0

Answer:

Step-by-step explanation:

A triangle must have three angles that add up to 180 degrees.

40 + 70 + 65 = 175, which is not 180, so it cannot create a triangle.

oksian1 [2.3K]3 years ago

3 0

To find measurements that don't make up a triangle, you need to find the measurements that don't make up 180 degrees, or on the three sides on the measurements, do not have A + B > C.

All triangle sides together make up 180 degrees. So we need to add up all of the angle measurements and find the ones, or we need to find A + B > C. When we find one that doesn't have these two things, it isn't a triangle.

A. 10° + 25° + 145° = 180° (this is a triangle)

B. 9m + 15m > 9m (this is a triangle)

C. 40° + 70° + 65° = 175° (this is not a triangle)

D. 6cm + 8cm > 10cm (this is a triangle)

The answer is C. because the answer is 175° which is less than 180°.

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3 years ago

Log(x+6)-log(x-3)=1 I need to show work, please show me how

Illusion [34]

Answer:

x = 4.

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8 0

3 years ago

Read 2 more answers

A city planner designs a park that is a quadrilateral with vertices at J(-3,1), K(1,3), L(5,-1), and M(-1,-3). There is an entra

Ksivusya [100]

The Quadrilateral is JKLM,

let $M_{JK}, M_{KL}, M_{LM}, M_{JM},$ be the midpoints of JK, KL, LM and JM respectively.

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Given any 2 point P(m,n) and Q(k,l),

the coordinates of the midpoint of the line segment PQ are given by the formula:

$M_{PQ}=( \frac{m+k}{2} ,
\frac{n+l}{2})$ ,

-------------------------------------------------------------------------------------------------

thus the coordinates of points $M_{JK}, M_{KL}, M_{LM}, M_{JM},$

are as follows:

$M_{JK}= (\frac{-3+1}{2}, \frac{1+3}{2})=(-1,2), \\\\M_{KL}= (\frac{1+5}{2}, \frac{3-1}{2}=(3,1), \\\\M_{LM}= (\frac{5-1}{2}, \frac{-1-3}{2})=(2, -2),\\\\ M_{JM}= (\frac{-3-1}{2}, \frac{1-3}{2})=(-2,-1)$

------------------------------------------------------------------------------------------------

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:

$|PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}
}$

------------------------------------------------------------------------------------------------

thus the distances connecting the opposite entrances can be calculated as follows:

$|M_{JK},M_{LM}|= \sqrt{ (-1-2)^{2} + (2-(-2))^{2} }= \sqrt{9+16}=5$

$|M_{KL}M_{JM}|= \sqrt{ (3-(-2))^{2} + (1-(-1))^{2}}= \sqrt{25+4}= \sqrt{29}=5.39$

Thus the total distance of the paths joining the opposite entrances is

5+5.39 units = 50 m + 53.9 m = 104 m (rounded to the nearest meter)

Answer: 104 m

8 0

3 years ago