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SVETLANKA909090 [29]
2 years ago
8

Brian has reduced his cholesterol level by 6% by following a strict diet and regular exercise. If his original level was 280, wh

at is his approximate cholesterol level now?
A. 17
B. 278
C. 263
D. 297
Mathematics
2 answers:
SashulF [63]2 years ago
6 0
The answer is c 263 I hope this helps
daser333 [38]2 years ago
3 0

Answer:

Maybe C?

Step-by-step explanation:

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To prove that ΔAED ˜ ΔACB by SAS, Jose shows that StartFraction A E Over A C EndFraction = StartFraction A D Over A B EndFractio
stich3 [128]

The other equality which must be stated by Jose is that angles BAC and BAE are congruent and their measures are equal.

<h3>What other congruence statements must Jose state?</h3>

It follows from the task content that Jose is trying to prove the congruence of both triangles by means of the Side-Angle-Side congruence theorem.

It therefore follows that since, Jose has identified that the ratio of corresponding sides are equal as indicated in the task content, the equality which Jose has to state is the angle congruence equality.

Read more on congruence theorem;

brainly.com/question/3168048

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7 0
2 years ago
Using the Breadth-First Search Algorithm, determine the minimum number of edges that it would require to reach
jekas [21]

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

   for(int i = 0;i < MAX;++i)

       id[i] = i;

}

int root(int x)

{

   while(id[x] != x)

   {

       id[x] = id[id[x]];

       x = id[x];

   }

   return x;

}

void union1(int x, int y)

{

   int p = root(x);

   int q = root(y);

   id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

   int x, y;

   long long cost, minimumCost = 0;

   for(int i = 0;i < edges;++i)

   {

       // Selecting edges one by one in increasing order from the beginning

       x = p[i].second.first;

       y = p[i].second.second;

       cost = p[i].first;

       // Check if the selected edge is creating a cycle or not

       if(root(x) != root(y))

       {

           minimumCost += cost;

           union1(x, y);

       }    

   }

   return minimumCost;

}

int main()

{

   int x, y;

   long long weight, cost, minimumCost;

   initialize();

   cin >> nodes >> edges;

   for(int i = 0;i < edges;++i)

   {

       cin >> x >> y >> weight;

       p[i] = make_pair(weight, make_pair(x, y));

   }

   // Sort the edges in the ascending order

   sort(p, p + edges);

   minimumCost = kruskal(p);

   cout << minimumCost << endl;

   return 0;

}

8 0
3 years ago
Can someone help me with this problem?
Diano4ka-milaya [45]
Can you show the answer choices but I believe is 18
3 0
2 years ago
Read 2 more answers
3. A big league pitching coach tries to limit his pitchers to 110 pitches per game. If the pitcher has
krek1111 [17]
110 minus 52 is 58 so the answer would be 58 more pitches
5 0
3 years ago
Find the equation of a line passing through the point (2, 3) and having a slope of 3.
Delvig [45]

Answer:

The answer to your question is the letter B) y = 3x - 3

Step-by-step explanation:

Data

Point = (2, 3)

slope = m = 3

Process

To solve this problem just substitute the values given in the slope-point equation.

Formula

               y - y1 = m(x - x1)

   x1 = 2      y1 = 3

-Substitution

              y - 3 = 3(x - 2)

-Expand

              y - 3 = 3x - 6

-Solve for y

             y = 3x - 6 + 3

-Result

             y = 3x - 3        

5 0
3 years ago
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