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2 years ago

Help me please and thank you

Mathematics

1 answer:

Feliz [49]2 years ago

3 0

Answer:

4.2 hours

Step-by-step explanation:

He spends 6 hours helping customers and 1.8 doing paperwork.

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5,30,180,1080 what is the common difference

KIM [24]

The given sequence is not arithmetic so, it doesn't has common difference.

8 0

2 years ago

Pls help me first get 10 you know

Luba_88 [7]

Option D, 63 cm

Explanation:

The scale of model is of local park is

This means that each dimension of the model is 21 times smaller than the actual park (to be developed in future)

Given -

Depth of the pond centi meter

Depth of the real pond will be 21 times of the depth of the model.

Thus , real pond's depth is equal to

Hence, option D is correct

7 0

2 years ago

One tenth the value of 2 in 8.524

Romashka [77]

85.25 would be one thenth of 8.524

3 0

2 years ago

Read 2 more answers

3. A carpenter is framing a window with wood trim where the length of the window is 6 and 2\3 feet. If the width of the window i

wel

We can see that window is in shape of rectangle. So the length of the required wood to frame window is equal to the perimeter of rectangle.

SO the length of rectangular window is $= 6 \frac{2}{3} = \frac{20}{3}$ feet.

Width of the rectangular window is = $7 \frac{3}{4} = \frac{31}{4}$ feet.

In general parameter of rectangle is = $2(l+b)$

So the parameter of window is = $2( \frac{20}{3} + \frac{31}{4}) = 2* \frac{(80+ 93)}{12} = 2* \frac{173}{12} = 28.834$

So the required length of wood to frame window is = 28.834 feet

3 0

3 years ago

Three vertices of parallelogram DEFG are D(-4,-2), E(-3,1) and F(3, 3). Find the coordinates of G.

Olin [163]

Answer:

Coordinates of G = $(2,0)$

Step-by-step explanation:

Given: Three vertices of parallelogram DEFG are D(-4,-2), E(-3,1) and F(3, 3).

To find: coordinates of G

Solution:

Midpoints of a side joining points $(a,b),\,(c,d)$ are given by $(\frac{a+c}{2},\frac{b+d}{2})$

Diagonals of a parallelogram bisect each other.

So,

Midpoint of DF = Midpoint of EG

Midpoint of DF = $(\frac{-4+3}{2},\frac{-2+3}{2})=(\frac{-1}{2},\frac{1}{2})$

Midpoint of EG = $(\frac{-3+x}{2},\frac{1+y}{2})$

Let coordinates of G be $(x,y)$

Therefore,

$(\frac{-1}{2},\frac{1}{2}) =(\frac{-3+x}{2},\frac{1+y}{2})\\\\\frac{-1}{2}=\frac{-3+x}{2},\,\frac{1}{2}=\frac{1+y}{2}\\\\-1=-3+x,\,1=1+y\\\\x=-1+3,\,y=1-1\\x=2,\,y=0$

So,

Coordinates of G = $(2,0)$

8 0

2 years ago