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Troyanec [42]
3 years ago
15

each course at college x is worth either 3 or 4 credits. The members of the men's swim team are taking a total of 53 courses tha

t are worth 174 credits. How many 3-credit courses and how many4-credit courses are being taken?
Mathematics
1 answer:
shusha [124]3 years ago
4 0
I can’t figure this one out
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Challenge you buy 3.18 pounds of oranges, 1.15 pounds of grapes, and 2.32 pounds of apples.
11111nata11111 [884]

Answer:

5

Step-by-step explanation:

Oranges: 3.46 $

Grapes: 1.36 $

Apple: They didn't leave you with the cost of the apple so I don't know

Add 3.46 plus 1.36 and you get 4.82. Then round that to 5.00.

8 0
3 years ago
fruit punch jucie boxes cost 0.35 per oz they come in boxes of 8.5 oz and 12.2 oz how many dose each box cost
Alisiya [41]
8.5 = $2.97
12.2 = $4.27
4 0
3 years ago
Read 2 more answers
How many liters each of a 35% acid solution and a 80% acid solution must be used to produce 60 liters of a 65% acid solution? (R
serg [7]

Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.

<h3>How many liters of each solution do we need to use?</h3>

First, we need to define the variables:

  • x = liters of the 35% acid used.
  • y = liters of the 80% acid used.

We know that we want to produce 60 liters of 65% acid, then we have the system of equations:

x + y = 60

x*0.35 + y*0.80 = 60*0.65

(in the second equation we wrote the percentages in decimal form).

To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:

x = 60 - y

Replacing that in the other equation:

(60 - y)*0.35 + y*0.80 = 60*0.65

y*(0.80 - 0.35) = 60*(0.65 - 0.35)

y*0.45 = 60*0.30

y = 60*0.30/0.45 = 40

So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

7 0
2 years ago
Two experiments are defined below. An event is defined for each of the experiments. Experiment I: Corrine rolls a standard six-s
-BARSIC- [3]

Answer: The correct answer is option C: Both events are equally likely to occur

Step-by-step explanation: For the first experiment, Corrine has a six-sided die, which means there is a total of six possible outcomes altogether. In her experiment, Corrine rolls a number greater than three. The number of events that satisfies this condition in her experiment are the numbers four, five and six (that is, 3 events). Hence the probability can be calculated as follows;

P(>3) = Number of required outcomes/Number of possible outcomes

P(>3) = 3/6

P(>3) = 1/2 or 0.5

Therefore the probability of rolling a number greater than three is 0.5 or 50%.

For the second experiment, Pablo notes heads on the first flip of a coin and then tails on the second flip. for a coin there are two outcomes in total, so the probability of the coin landing on a head is equal to the probability of the coin landing on a tail. Hence the probability can be calculated as follows;

P(Head) = Number of required outcomes/Number of all possible outcomes

P(Head) = 1/2

P(Head) = 0.5

Therefore the probability of landing on a head is 0.5 or 50%. (Note that the probability of landing on  a tail is equally 0.5 or 50%)

From these results we can conclude that in both experiments , both events are equally likely to occur.

3 0
3 years ago
Help me pls AAAAAAAA
erastovalidia [21]

Answer:

10/3 liters

Step-by-step explanation:

Divide (4/3) by 2, then multiply by 5

4 0
3 years ago
Read 2 more answers
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