Answer:
The length of OR = 3.12
Step-by-step explanation:
In a parallelogram:
LM = 4.12
MN = 4
LN = 5 = 2.5 (divided by 2)
OM = 6.4
where LN and OM are diagonals. We will find the length of OR.
Now by applying the Pythagorean theorem:
b = √c²-a²
OR= √(4)²-(2.5)²
OR = √16-6.25
OR = √9.75
OR = 3.12
Thus the length of OR = 3.12 ...
II. f(x) doubles for each increase of 1 in the x values. Thus, r must be 2, and so we our ar^1 = 6 from ( I ) above becomes f(x) = a*2^x. Applying the restriction ar^1 = 6 results in f(1) = a*2^1 = 6, or a = 3.
Then f(x) = ar^x becomes f(x) = 3*2^2 (Answer A)
Answer:
3x^2+6x+4 is the answer :D
Answer:
84
Step-by-step explanation:
Let x = the test
(x + x + ( x - 6))/3=82
((3x - 6)/3) • 3= 82 • 3
3x - 6 + 6 = 246 + 6
<u>3x</u> = <u>252</u>
3 3
x = 84
