Total of 10 persons, out of which 6 are women.
So
probability of choosing the first woman = 6/10
probability of choosing the second woman = 5/9
probability of choosing the third woman = 4/8
Since we want all 3 steps to be a success, we need to have success in each of the steps, and the overall probability is given by the multiplication rule:
P(all 3 are women)=6/10*5/9*4/8=120/720=1/6
Step 1: plug in 5 and 2 for your X and Y
Step 2: multiply 8*X or in this case 8*5 and you will get 40
Step 3: multiply 3*Y or in this case 3*2 and you will get 6
Step 4: subtract 40-6 and you will get 34
Answer:
21
Step-by-step explanation:
![\left[\begin{array}{cc}5&9\\-6&9\end{array}\right] +6\left[\begin{array}{cc}-5&2\\7&8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%269%5C%5C-6%269%5Cend%7Barray%7D%5Cright%5D%20%2B6%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-5%262%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Multiply the second matrix by 6.
![\left[\begin{array}{cc}5&9\\-6&9\end{array}\right] +\left[\begin{array}{cc}-30&12\\42&48\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%269%5C%5C-6%269%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-30%2612%5C%5C42%2648%5Cend%7Barray%7D%5Cright%5D)
Add the corresponding cells in each matrix.
![\left[\begin{array}{cc}5-30&9+12\\-6+42&9+48\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5-30%269%2B12%5C%5C-6%2B42%269%2B48%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{cc}-25&21\\36&57\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-25%2621%5C%5C36%2657%5Cend%7Barray%7D%5Cright%5D)
Y=3
to solve this you just substitute 4 in for x into the equation and solve for y. since negative 3 plus 7 is 4, y=4
Um.... 368 369 370 371 372 372 374 375 376 377 378 379 etc
