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Natali [406]
2 years ago
9

Hypotenuse of 9 and 12

Mathematics
2 answers:
vladimir1956 [14]2 years ago
7 0

Answer:

108

Step-by-step explanation:

Hope I help :)

Dominik [7]2 years ago
5 0
“15 feet” is your answer!
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An architect designs a castle tower for a new attraction at a popular amusement park. Blueprints of the tower, which is in the s
marin [14]

Answer:

<u>The surface area of the tower is 5,218.1 m²</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Height of the blueprint = 47 cm

Length of the blueprint = 23 cm

Width of the blueprint = 25 cm

Scale factor 1 : 96

2. Calculate the actual surface area of the tower and enter your answer in square meters with two decimal places.

Let's calculate the measurements of the actual tower:

Height of the blueprint = 47 * 96 = 4,512 cm = 45.12 m

Length of the blueprint = 23 * 96 = 2,208 cm = 22.08 m

Width of the blueprint = 25 * 96 = 2,400 cm = 24 m

Now, let's calculate the surface area of the tower, this way:

Surface area of the tower = 2* (24 * 22.08) + 2 * (45.12 * 22.08) + 2 * (45.12 * 24)

Surface area of the tower = 1,059.84 + 1,992.5 + 2,165.76

<u>Surface area of the tower = 5,218.1 m²</u>

4 0
3 years ago
Which points are solutions to the linear inequality y &lt; 0.5x + 2? Select three options. (–3, –2) (–2, 1) (–1, –2) (–1, 2) (1,
Fantom [35]

Answer:

A.C.E

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Please help. thank you
MaRussiya [10]

Answer: what do need help on

Step-by-step explanation:

4 0
2 years ago
I NEED AN MATH EXPERT ON THIS..Ill give brainless and extra points​
abruzzese [7]
I think it’s 90% cuz it’s 45/50 therefore 90/100
8 0
3 years ago
The length of a rectangle is 5 meters less than twice the width. If the area of the rectangle is 273 meters, find the dimensions
AleksandrR [38]

The length of the rectangle = 16 meters

The width of the rectangle = 10.5 meters

<u>Step-by-step explanation</u>:

Given that,

The Area of the rectangle is 273.

<u><em>Step 1</em></u><em> :</em>

Let, the width of the rectangle be 'x'

The length of the rectangle is 2x - 5

<u><em>Step 2</em></u><em> :</em>

Area of the rectangle = length \times width

                             273 = (2x - 5) x

                             273 = 2x^2 - 5x

<u><em>Step 3</em></u><em> :</em>

The equation formed is 2x^2 - 5x -273 = 0

a= coefficient of x^2 = 2

b= coefficient of x = -5

c = constant = -273

Find the roots of the equation, to find the width.

<u><em>Step 4</em></u><em> :</em>

Find the roots using factorizing method,

ac = 2\times-273 = -546 and b= -5

Factorizing -546 as -26\times21

The product of -26\times21 = -546

The sum of -26 + 21 = -5

<u><em>Step 5</em></u><em> :</em>

The roots of the equation 2x^2 - 5x -273 = 0 are x= -26/2 and x= 21/2

The values of x are x= -13 and x= 10.5

Since the width cannot be a negative value, neglect x= -13

<u><em>Step 6</em></u><em> :</em>

Therefore,

The width of the rectangle = 10.5 meters

The length of the rectangle = 2x-5

                                                = 2(10.5) - 5

                                                = 21 - 5

                                    length = 16 meters

5 0
3 years ago
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