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qwelly [4]
2 years ago
14

Which classification describes the triangle with side lengths of 10, 16, and 20?

Mathematics
1 answer:
11111nata11111 [884]2 years ago
5 0
Scalene triangles have no congruent sides
You might be interested in
What is the gcf of 48m^5n and 81m^2n^2
JulijaS [17]

Answer:

gcf is 3m^2n

Step-by-step explanation:

we are given

48m^5n and 81m^2n^2

Firstly, we will find factors of both expression

48m^5n=2\times 2\times2\times 2\times 3\times m^2\times m^3\times n

81m^2n^2=3\times 3\times 3\times 3\times m^2\times n\times n

now, we will find common factors among them

we can see that

For finding gcf, we always find common factors

so,

common terms are 3,m^2 and n

so, gcf is

=3\times m^2\times n

=3m^2n


8 0
2 years ago
If f(x) = 2x + 3 and g(x) = x^2 + 1,find f(g(3)).<br> A.) 23<br> B.) 47<br> C.) 82<br> D.) 90
marta [7]
The answer is A). 23. 
<span>g(x)= 2x + 3 </span>
<span>g(x) = x^2 + 1 </span>
<span>g(3) = 10 </span>
<span>f(g(3)) </span>
<span>= f(10) </span>
<span>= 23 </span>
6 0
3 years ago
If angle ABD is 90 degrees. Select all of the angles that measure 42 degrees.
m_a_m_a [10]

Answer:

Measure of angle 2 and angle 4 is 42°.

Step-by-step explanation:

From the figure attached,

m∠ABC = 42°

m(∠ABD) = 90°

m(∠ABD) = m(∠ABC) + m(∠DBC)

90° = 43° + m(∠DBC)

m(∠DBC) = 90 - 43 = 47°

Since ∠ABC ≅ ∠4 [Vertical angles]

m∠ABC = m∠4 = 42°

Since, m∠3 + m∠4 = 90° [Complimentary angles]

m∠3 + 42° = 90°

m∠3 = 90° - 42°

        = 48°

Since, ∠5 ≅ ∠3 [Vertical angles]

m∠5 = m∠3 = 48°

m∠3 + m∠2 = 90° [given that m∠2 + m∠3 = 90°]

m∠2 + 48° = 90°

m∠2 = 90 - 48 = 42°

m∠3+ m∠4 = 90° [Since, ∠3 and ∠4 are the complimentary angles]

48° + m∠4 = 90°

m∠4 = 90 - 48 = 42°

Therefore, ∠2 and ∠4 measure 42°.

5 0
3 years ago
Suppose a family starts out 50 miles from home at time t = 0. They travel away from home at a constant speed of 45 miles an hour
skelet666 [1.2K]
50 miles, t=0 is the start
45 miles each 1 hour

A. d= 45•t+50
3 0
3 years ago
Read 2 more answers
Find the standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8.
Gala2k [10]
Vertex is directly in middle of directix and focus

distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice

it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2
5 0
3 years ago
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