All categories

1 year ago

Please help me! in need of help due tomorrow!

Mathematics

1 answer:

julsineya [31]1 year ago

3 0

Answer:

Step-by-step explanation:

(1). A = π r²

A = 4 π

Area of shaded region is $\frac{4\pi *260}{360}$ = $\frac{26}{9} \pi$ or $\frac{26\pi }{9}$

(2). C = 4 π

In this case, the length of the bigger arc and the area of shaded region happen to be the same.

The length of the arc ADB is $\frac{26}{9} \pi$ or $\frac{26\pi }{9}$

You might be interested in

In the decimal 55.555, which is 1/10 the value of the 5 in the tenths place?

inna [77]

Answer:

55.555

Step-by-step explanation:

1/10 × 1/10 = 1/100

The value in the hundredths place is 1/10 the value in the tenths place.

55.555

7 0

2 years ago

Let A {a, b, c, d}. Find the power set of A, PA

Nina [5.8K]

$A=\{a,b,c,d\}\\|A|=4\\\mathcal{P}(A)=2^4=16$

8 0

3 years ago

PLEASE HELPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OLga [1]

The set of numbers in the Collatz Conjecture are 1, 4, 2, 1, 4, 2, 1, 4, 2....

<h3>How to generate the numbers in the Collatz Conjecture</h3>

To start with, we make use of the following starting point:

Starting point = 1

The rule is given as:

If the last number is odd, multiply it by 3 and add 1.
If the last number is even, divide the number by 2.

1 is an odd number.

So, we use the first rule

So, we have:

1 * 3 + 1 = 4

4 is an even number.

So, we use the second rule

So, we have:

4/2 = 2

So, the first three numbers in the Collatz Conjecture are:

1, 4, 2

Using the given rules, we have:

1, 4, 2, 1, 4, 2, 1, 4, 2....

The above means that there is only one set of repeating numbers in the Collatz Conjecture.

Hence, the set of numbers in the Collatz Conjecture are 1, 4, 2, 1, 4, 2, 1, 4, 2....

Read more about sequence at:

brainly.com/question/7882626

#SPJ1

5 0

2 years ago

Does 10 hours to 6 hours increase or decrease

Varvara68 [4.7K]

Depend on the time frame, A.M or P.M.

8 0

3 years ago

An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a

MAVERICK [17]

Answer:

Probability Mass Function:

x: 0 1 2 3

P(x): 0.000064 0.004608 0.115902 0.884736

Step-by-step explanation:

We are given the following information:

We treat correct classification as a success.

P(correct classification) = 0.96

Then the number of classification follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3 and x = 0, 1, 2, 3

We have to evaluate:

$P(x = 0)\\= \binom{3}{0}(0.96)^0(1-0.96)^3\\=0.000064$

$P(x = 1)\\= \binom{3}{1}(0.96)^1(1-0.96)^2\\=0.004608$

$P(x = 2)\\= \binom{3}{2}(0.96)^2(1-0.96)^1\\=0.115902$

$P(x = 3)\\= \binom{3}{3}(0.96)^3(1-0.96)^0\\=0.884736$

PMF:

x: 0 1 2 3

P(x): 0.000064 0.004608 0.115902 0.884736

8 0

3 years ago

Please help me! in need of help due tomorrow!​

Please help me! in need of help due tomorrow!