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Ivahew [28]
3 years ago
14

What is the simplest fraction whose value is equal to the number (red heart) depicted on this number line. (Give your answer as

a fraction, not a mixed number. "Simplest fraction" means the numerator and denominator should have no common divisor greater than 1. : Look closely at the numbers on the number line. (red heart) is between 2 and 3. There are 6 tick marks between 2 and 3. How many regions do those tick marks split the number line into?

Mathematics
1 answer:
maks197457 [2]3 years ago
6 0

Answer:

simplest fraction: 2 1/3         the tick marks split the number into 7 regions

Step-by-step explanation:

The red heart is on the 2 tick mark of the 6 ticks between 2 and 3. The answer is 2 2/6 which after simplifying if equal to 2 1/3.

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A home improvement store rents vacuums at $45 for the first day and $22 for each day thereafter. If y represents the total cost
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Answer with explanation:

Amount charged by Home Improvement Store for first day=$ 45

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x=Number of days Rented

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→→Total amount charged(y)=45+22x-22

→→→y=22x+23

is, the required function.

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What is the square root of negative 17/16
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4 0
3 years ago
Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)
babunello [35]

\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k

We want to find f(x,y,z) such that \nabla f=\vec F. This means

\dfrac{\partial f}{\partial x}=x^2+y

\dfrac{\partial f}{\partial y}=y^2+x

\dfrac{\partial f}{\partial z}=ze^z

Integrating both sides of the latter equation with respect to z tells us

f(x,y,z)=e^z(z-1)+g(x,y)

and differentiating with respect to x gives

x^2+y=\dfrac{\partial g}{\partial x}

Integrating both sides with respect to x gives

g(x,y)=\dfrac{x^3}3+xy+h(y)

Then

f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)

and differentiating both sides with respect to y gives

y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C

So the scalar potential function is

\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}

By the fundamental theorem of calculus, the work done by \vec F along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it L) in part (a) is

\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}

and \vec F does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them L_1 and L_2) of the given path. Using the fundamental theorem makes this trivial:

\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3

\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4

8 0
3 years ago
Please actually help me. ill give brainliest if you explain your answer.
meriva

Answer:

subtract 11 from both sides

Step-by-step explanation:

-3x+11=44

-3x=33

x=-11

4 0
3 years ago
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