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3 years ago

What is the mode of the following numbers? 10, 6, 4, 4, 6, 4, 1

Mathematics

1 answer:

tia_tia [17]3 years ago

8 0

Answer:

Step-by-step explanation:

10 = one time

6 = two times

4 = three times

1 = one time

mode means most, which number is there the most of

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At the candy store there are 420 gumdrops and 280 chocolate bars, for a total of 700 candies all together. What is the ratio of

Mekhanik [1.2K]

Answer:

5 : 2

Step-by-step explanation:

Given that:

Number of gumdrops = 420

Number of chocolate bars = 280

Total Number of candies = 700

To find:

The ratio of candies to chocolate bars = ?

Solution:

First of all, let us discuss the method to find the ratio of any two quantities.

Suppose, we need to find the ratio of two numbers $p$ and $q$ .

Then to find the ratio $p:q$ , we need to divide p by q and represent it in the simplest form $\frac{a}{b}$ such that a and b can not be divided further.

Here, to find the ratio of candies to chocolate bar:

$Ratio = \dfrac{\text{Number of candies}}{\text{Number of chocolate bars}}\\\Rightarrow \dfrac{700}{280}$

Here, we can simplify the fraction by dividing the numerator and denominator by 10 first:

$\dfrac{70}{28}$

Now, let us divide the numerator and denominator by 14:

$\dfrac{5}{2}$

So, the ratio is <em>5 : 2</em>

6 0

2 years ago

6 lb 4 oz − 5 lb 10 oz =

FinnZ [79.3K]

The answer to your problem is 10 oz

5 0

2 years ago

Read 2 more answers

Please help if you can:)

geniusboy [140]

Answer:

(-2,17) i think i am not sure

Step-by-step explanation:

8 0

3 years ago

Choose the slope of the line that passes through (2,3) and (-4,5)

Nady [450]

5-3/-4-2=-2/6 the slope of the line is -2/6. This is the case because you do y1-y2 over x1-x2. ANSWER -2/6

7 0

3 years ago

One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides

Elina [12.6K]

<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

The side of the square is 10 ft.
One of the vertices of an equilateral triangle is on the vertex of a square.
Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

$\mathbf{(1)} \ x^2=100+y^2$

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

$y+(10-y)=10$

Therefore, for Triangle 3, we have that by Pythagorean theorem:

$(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2$

Matching equations (1) and (2):

$2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0$

Using quadratic formula:

$y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68$

Finding x from (1):

$x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft$

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0

3 years ago

Read 2 more answers