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lidiya [134]
4 years ago
9

What is the correct formula for xenon hexafluoride? XeF XeF6 Xe6F6 Xe6F

Chemistry
2 answers:
Black_prince [1.1K]4 years ago
7 0

Answer:The formula for xenon hexafluoride is XeF6

Explanation:

Vinil7 [7]4 years ago
3 0
Hexa- means six
"hexa-" and it is in front of the fluoride so that means we have 6 fluorines
Answer:
xenon hexafluoride → XeFl_{6}

Any questions?
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In an experiment, mice were fed glucose (C₆H₁₂O₆) containing a small amount of radioactive carbon. The mice were closely monitor
Luden [163]
<h3>Answer:</h3>

Carbon dioxide

Explanation:

  • Cellular respiration involves a break down of sugars such as glucose to yield energy in the form of ATP and water together with carbon dioxide as byproducts.
  • In this case, when mice are fed with glucose, cellular respiration takes place breaking down glucose to yield energy in the form of ATP, water and carbon dioxide.
  • Therefore, the radioactive carbon in glucose showed up in carbon dioxide, since the carbon in glucose ends up in carbon dioxide.
8 0
3 years ago
How many atoms of Na are in 1.89 mol of Na?
atroni [7]

Answer:

1.138158E24 atoms or 1.14 x 10^24 atoms

Explanation:

To find atoms/particles from moles you just want to convert using avogadro's number which is 6.022 x 10^23

1.89 mol x 6.022 • 10^23

———— = 1.138158E24 atoms

1 mol

so 1.138158E24 atoms or 1.14 x 10^24 for scientific notation

hope this helps :)

5 0
3 years ago
A kid on a playground swing makes 6 complete to-and-fro swings each 30 seconds.
Virty [35]
The frequency of swings is 12 ans the perios of swining is 3 min.
6 0
3 years ago
Identify limiting and excess reagents when 25g of nitrogen reacts with 25g of hydrogen. How many grams of ammonia gas are formed
Makovka662 [10]

Answer:

Nitrogen is limiting reactant while hydrogen is in excess.

Explanation:

Given data:

Mass of N₂ = 25 g

Mass of H₂ = 25 g

Mass of ammonia formed = ?

Solution:

Chemical equation:

N₂ + 3H₂    →     2NH₃

Number of moles of Nitrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 28 g/mol

Number of moles = 0.89 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 25 g/ 2 g/mol

Number of moles = 12.5 mol        

Now we will compare the moles of both reactant with ammonia.

                   H₂            ;             NH₃

                    3             :              2

                    12.5        :            2/3×12.5 = 8.3

                 

                   N₂            ;             NH₃

                    1              :              2

                    0.89        :            2×0.89 = 1.78

The number of moles of ammonia produced by nitrogen are less thus nitrogen is limiting reactant while hydrogen is in excess.

7 0
4 years ago
Do meteorologists need instruments
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6 0
3 years ago
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