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Deffense [45]
3 years ago
13

Please help- Determine the relationship between potential and kinetic energy in a system.

Physics
1 answer:
Alex Ar [27]3 years ago
8 0

Answer:

See the explanation below.

Explanation:

At the highest point is where potential energy is maximum and kinetic energy is zero.

Because potential energy is defined as the product of mass by gravitational acceleration by height, this is expressed within the following equation:

E_{pot}=m*g*h

where:

Epot = potential energy [J]

m = mass [kg]

g = gravity acceleration [m/s²]

h = elevation [m]

As we can see, if the body is located at the highest point with respect to the ground, potential energy has the maximum value. Meanwhile, the kinetic energy is zero because there is no movement.

At the lowest point is where the kinetic energy is maximum and the potential energy es zero.

When the body is in the lowest location, the height is zero, therefore potential energy is zero (h = 0). But the body is moving with a certain velocity that is we have kinetic energy.

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A charged particle of mass 6.00 mg moves with a speed of 4.00 km/s in a direction that makes an angle of 37o above the positive
AysviL [449]

Answer:

Explanation:

mass of charged particle m = 6 x 10⁻³ kg .

speed of particle   v  = 4 x 10³ m /s

speed of particle perpendicular to magnetic field = v sin37

= 4 x 10³ sin37

= 2.41 x 10³ m / s

Force on charged particle

= B q v , B is magnetic field , q is charge on particle and v is velocity perpendicular to B

Force = ma

= 6 x 10⁻³ x 8

= 48 x 10⁻³

Force = Bqv

48 x 10⁻³ = 5 x 10⁻³ q x  2.41 x 10³

q = 48 x 10⁻³  / (5 x 2.41)

= 3.98 x 10⁻³C.

5 0
4 years ago
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In anticipation of a long 10 upgrade, a bus driver accelerates at a constant rate of 5 ft/s2 while still on a level section of a
fgiga [73]

Answer:

S = 20903.4 ft

Explanation:

First we will determine the acceleration of the bus while it is moving upward

The equilibrium  equation would be

F - W sin\theta = ma'\\ma - W sin\theta = ma'\\m = \frac{W}{g} \\\frac{W}{g}*a - W sin\theta = \frac{W}{g} * a'\\\frac{a}{g} - sin\theta = \frac{a'}{g}\\\frac{x}{y} \frac{5}{32.2} - sin 10 = \frac{a'}{32.2} \\\a' = -0.59

Let the displacement be S_0

As per newton's third law of motion

v^2 -u^2 = 2as\\u = 80 \frac{mi}{h} =   117.33\frac{ft}{s}\\v = 50 \frac{mi}{h} =   73.33\frac{ft}{s}\\73.33 ^ 2 - 117.33^2 =  2 * (-0.59) * (S-S_0)\\\\S_0 = 0\\S = 20903.4

3 0
3 years ago
A​ hot-air balloon is 150 ft above the ground when a motorcycle​ (traveling in a straight line on a horizontal​ road) passes dir
Katyanochek1 [597]

Answer:

 dR/dt = 10.2 ft / s

Explanation:

Let's work this problem by finding the distance between the balloon and the motorcycle and then drift for the speed change of the distance

Balloon

      y = y₀ +v_{oy} t

Motorcycle

      x = v₀ₓ t

Distance, let's use Pythagoras' theorem

      R² = x² + y²

      R² = (v₀ₓ t)² + (y₀ + v_{oy} t)²

     v₀ₓ = 88 ft / s

     v_{oy} = 8 ft / s

     y₀ = 150 ft

     R² = (8 t)² + (150 + 8 t )²

     R² = 64 t² + (150 + 8t )²

This is the expression for the distance between the two bodies, the rate of change is the derivative with respect to time (d / dt)

         2RdR / dt = 64 2 t + 2 (150 + 8t) 8

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dR/dt = (1200 +128 t)/R

Let's calculate for the time of 10 s

        dR / dt = (1200 + 128 10) / R = 2480 /R

       R = √ [64 10² + (150 + 8 10)²

       R = √ [6400 + 52900]

       R = 243.5 ft

       dR / dt = (2480) / 243.5

       dR / dt = 10.2 ft / s

8 0
4 years ago
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seropon [69]

Answer:

Lilly's speed is two times John's speed.

Explanation:

m = Mass

a = Acceleration

t = Time taken

u = Initial velocity

v = Final velocity

The force they apply on each other will be equal

F=ma\\\Rightarrow a_l=\frac{F}{m_l}

F=ma\\\Rightarrow a_j=\frac{F}{2m_l}\\\Rightarrow a_j=\frac{1}{2}a_l

v=u+at\\\Rightarrow v_l=0+\frac{F}{m_l}\times t\\\Rightarrow v_l=a_lt

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Hence, Lilly's speed is two times John's speed.

4 0
3 years ago
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