Please help- Determine the relationship between potential and kinetic energy in a system.
1 answer:
Answer:
See the explanation below.
Explanation:
At the highest point is where potential energy is maximum and kinetic energy is zero.
Because potential energy is defined as the product of mass by gravitational acceleration by height, this is expressed within the following equation:
where:
Epot = potential energy [J]
m = mass [kg]
g = gravity acceleration [m/s²]
h = elevation [m]
As we can see, if the body is located at the highest point with respect to the ground, potential energy has the maximum value. Meanwhile, the kinetic energy is zero because there is no movement.
At the lowest point is where the kinetic energy is maximum and the potential energy es zero.
When the body is in the lowest location, the height is zero, therefore potential energy is zero (h = 0). But the body is moving with a certain velocity that is we have kinetic energy.
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Answer:
(a):
(b):
Explanation:
<u>Given:</u>
- Charge on one sphere,
- Charge on second sphere,
- Separation between the spheres,
Part (a):
According to Coulomb's law, the magnitude of the electrostatic force of interaction between two static point charges is given by
where,
k is called the Coulomb's constant, whose value is
From Newton's third law of motion, both the spheres experience same force.
Therefore, the magnitude of the force that each sphere experiences is given by
The negative sign shows that the force is attractive in nature.
Part (b):
The spheres are identical in size. When the spheres are brought in contact with each other then the charge on both the spheres redistributes in such a way that the net charge on both the spheres distributed equally on both.
Total charge on both the spheres,
The new charges on both the spheres are equal and given by
The magnitude of the force that each sphere now experiences is given by
Answer:
1.55 m
Explanation:
The potential produced by a point charge, is inversely proportional to the distance from the charge to the point where the potential is being calculated, as follows:
As it only depends from the distance r, we can conclude that if the potential is the same for any point to a distance r from the point charge, the equipotencial surface must be a sphere of radius r.
Replacing q = +1.7*10⁻⁸ C, and k = 9*10⁹ N*m²/C², and V, by 120 V and 54 V, we can find the distance from the charge, to the points where we are calculating the potential V, as follows:
The distance between both points, is just the difference between the radius of both spheres, as follows:
r₂ - r₁ = 1.55 m