Power = work/time
Work = force * distance
(2000 N * 200 m) / 10 s = 40,000 Joules
Displacement = (straight-line distance between the start point and end point) .
Since the road east is perpendicular to the road north,
the car drove two legs of a right triangle, and the magnitude
of its final displacement is the hypotenuse of the triangle.
Length of the hypotenuse = √ (215² + 45²)
= √ (46,225 + 2,025)
= √ 48,250
= 219.7 miles .
Answer:
8m/s
Explanation:
Average Speed = distance / time = 400/50 = 8m/s
Answer:
355 m/s
Explanation:
Distance = 605 km
Initial speed = 
= 284 m/s
Final velocity = 
= 426 m/s
Average speed = ?
There is two method two find average speed. In first method, using 3rd equation of motion, we find acceleration.
Then using first equation of motion, we find time
Then using the formula of average velocity, we find average velocity
Second method is very simple
355 m/s
For an inelastic collision where coefficient of restitution,e, is equal to 0, the momentum is conserved but not the kinetic energy. So, there is addition or elimination of kinetic energy.
On the otherhand, when e = 1, like for an elastic collision, kinetic energy and momentum is conserved. Thus, the system's kinetic energy is unchanged.
