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Jlenok [28]
3 years ago
13

Helpp how do we know if an equation is a linear relation​

Mathematics
1 answer:
antoniya [11.8K]3 years ago
6 0

Answer:

Simplify the equation as closely as possible to the form of y = mx + b. Check to see if your equation has exponents. If it has exponents, it is nonlinear. If your equation has no exponents, it is linear.

Step-by-step explanation:

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A community organization wants to determine area support for the construction of a new skate park in the center of town. The org
Black_prince [1.1K]

Answer:  I just took the test, and the answer is 'Assign each taxpayer in town a number and then randomly select 500 of these numbers.'

Step-by-step explanation: Happy Pride Month!!

6 0
3 years ago
Find the circumference of the taxicab circle with a radius of 9.
AnnZ [28]
C=2πr=2(9)π=18π......
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7 0
3 years ago
When she graduates college Linda will owe 43,000 in student loans. The interest rate on the federal Liana is 4.5 % and the rate
Amanda [17]

Answer:

federal loan amount = $29,000

private loan amount = $14,000

Step-by-step explanation:

Total amount is 43000

Let amount in federal be f

and

amount in private be 43,000 - f

Interest rate at federal is 0.045

Interest rate at private is 0.02

THus, we can form the equation shown below and solve:

f(0.045) + (43,000 - f)(0.02) = 1585

0.045f +860 - 0.02f = 1585

0.025f = 725

f = 29,000

and on private = 43,000 - 29,000 = 14,000

Hence

federal loan amount = $29,000

private loan amount = $14,000

6 0
3 years ago
10.The sum of first 16 terms of the AP: 10, 6 ,2, ....is
madam [21]

Answer:

<h2>               - 320</h2>

Step-by-step explanation:

a₁ = 10

a₂ = 6

d = a₂  - a₁ = 6 - 10 = -4

n = 16

a₁₆ = a₁ + (n-1)•d = 10 + (16-1)•(-4) = 10 - 60 = -50

S_{n}=\dfrac{a_1+a_n}{2}\cdot n\\\\\\S_{16}=\dfrac{10-50}{2}\cdot 16=-40\cdot8=-320

4 0
3 years ago
Given sinx=3/5 and x is in quadrant 2, what is the value of tan(x/2)
xxMikexx [17]
X is in the second quadrant means that x/2 is in the first quadrant.


Consider the right triangle drawn in the figure. Let tan(x/2)=a.

Then, let the length of the opposite side to x/2 be a, the adjacent side be 1 and the hypotenuse be square root of a squared +1, as shown in the figure.

sin(x/2)=|opp side|/ |hypotenuse| =  \frac{a}{ \sqrt{ a^{2}+1 } }

cos (x/2) = |adj side|/ |hypotenuse| =  \frac{1}{ \sqrt{ a^{2}+1 } }


from the famous identity: sin(2a)=2sin(a)cos(a), we have:

2sin(x/2)cos (x/2)=sin(x)

thus

2* \frac{a}{ \sqrt{ a^{2}+1 } }*\frac{1}{ \sqrt{ a^{2}+1 } }= \frac{3}{5}

2* \frac{a}{  a^{2}+1 }= \frac{3}{5}

10a=3 a^{2} +3

3 a^{2}-10a +3=0

(3a-1)(a-3)=0

thus a=1/3 or a=3


thus tan(x/2)=1/3 or tan(x/2)=3


Answer: {1/3, 3}

3 0
3 years ago
Read 2 more answers
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