Answer:
B.) y=csc x
Step-by-step explanation:
The cosecant function has a minimum magnitude of 1, so its range excludes any values in the range -1 < y < 1.
y = csc(x) . . . has a range that does not include -0.8
Taking into account the discriminant of a cuadratic function, values of c less than
cause the quadratic equation -x²+3x+c=0 to have no real number solutions.
<h3>Discriminant of a cuadratic function</h3>
The function f(x) = ax² + bx + c with a, b, c real numbers and a ≠ 0, is a function quadratic expressed in its polynomial form (It is so called because the function is expressed by a polynomial).
The following expression is called discriminant:
Δ= b²- 4×a×c
The discriminant determines the amount of roots of the function. The roots are those values of x for which the expression is 0, so it graphically cuts the x-axis.
Then:
- If Δ <0 the function has no real roots and its graph does not intersect the x-axis.
- If Δ> 0 the function has two real roots and its graph intersects the x-axis at two points .
- If Δ = 0 the function has a real root and its graph intersects the x-axis at a single point that coincides with its vertex. In this case the function is said to have a double root.
<h3>Value of c</h3>
In this case, for the quadratic equation -x²+3x+c=0 you know:
If the function has no real roots, the discriminant is less than zero (Δ <0). This is: b²- 4×a×c < 0
Substituting the corresponding values, you get:
3²- 4×(-1)×c < 0
Solving:
9 + 4×c < 0
4×c < -9
c< (-9)÷4
c< ![-\frac{9}{4}](https://tex.z-dn.net/?f=-%5Cfrac%7B9%7D%7B4%7D)
Finally, values of c less than
cause the quadratic equation -x²+3x+c=0 to have no real number solutions.
Learn more about the discriminant of a cuadratic function:
brainly.com/question/14477557
<h3>
<u>Answer:</u></h3>
Average of salary of Anne and David is 1.25 of Peter's Salary
<h3>
<u>Explanation:</u></h3>
In the question, relations between salaries of Peter, Anne, and David is given. From the given relations, we need to make few equations and calculate the average of Anne and David in terms of Peter's Salary.
Let us assume Peter's Salary as P.
Then we can calculate Anne's salary A =
.
Also David's salary = D = ![2 \times P](https://tex.z-dn.net/?f=2%20%5Ctimes%20P)
Average of Anne's and David's salary = ![\frac{A+D}{2}](https://tex.z-dn.net/?f=%5Cfrac%7BA%2BD%7D%7B2%7D)
Average of Anne's and David's salary = ![\frac{\frac{P}{2} + 2 \times P}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7BP%7D%7B2%7D%20%2B%202%20%5Ctimes%20P%7D%7B2%7D)
Average of Anne's and David's salary = ![\frac{5 \times P}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%20%5Ctimes%20P%7D%7B4%7D)
Average = 1.25 \times P
Answer:
<6,7>
Step-by-step explanation:
u is the vector <5,1>
v is the vector < 1,6>
Add the corresponding components
< 5,1> + <1,6> = <5+1, 1+6> = <6,7>