Can someone help asap!!

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago

HELPP MEE PLSSS HELPP

julia-pushkina [17]

Answer:

angle N is 79, angle K is 22, angle P is 81, angle D is 76

Step-by-step explanation:

all of the angles should add up to 180 degrees so add the two angles you have and subtract them from 180

6 0

3 years ago

Read 2 more answers

The Pew Research Center reported that 73% of Americans who own a cell phone also use text messaging. In a recent local survey, 1

AnnZ [28]

Answer:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

Step-by-step explanation:

Information provided

n=200 represent the sample size slected

X=155 represent the cell phone owners used text messaging

$\hat p=\frac{155}{200}=0.775$ estimated proportion of cell phone owners used text messaging

$p_o=0.73$ is the value to verify

$\alpha=0.1$ represent the significance level

We need to conduct a z test for a proportion

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true proportion of cell phone owners used text messaging is different from 0.73 so then the system of hypothesis are:

Null hypothesis: $p=0.73$

Alternative hypothesis: $p \neq 0.73$

The statistic to check this hypothesis is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

6 0

3 years ago

Will mark as brainiest.

EleoNora [17]

Answer: let

x = # cans produced

fixed cost = $50,000

variable cost = $8/can

Step-by-step explanation: I am ultimate pro at this

5 0

3 years ago

What is the missing factor in the equation? Assume x0 and y0.

denpristay [2]

Answer:

y^3/4x

Step-by-step explanation:

Given that the expression 6x^2/5y multiplied by some unknown gives answer as 3xy^2/10

We know that if ab = c, the b = c/a

Using the same principle, we have

unknown value = 3xy^2/10 divided by 6x^2/y

Use the fact that a/b divided by c/d = ad/bc

We get unknown = 5y(3xy^2)/6x^2 (10)

=15xy^3/60x^2

Simplify the constant part 15/60 as 1/4

xy^3 /x^2y

X term becomes x/x^2 = 1/x

so multiplying term =y^3/4x

5 0

3 years ago