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Vedmedyk [2.9K]

3 years ago

9

The number of molecules of ammonia, NH₃, in water solution required for complete ionization of one molecule of sulfuric acid, H₂

SO₄, is
1
2
3
4
6

Please Explain!!!

1 answer:

Natalija [7]3 years ago

6 0

Answer:

6 that will be the answer

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A student obtains a mixture of the chlorides of two unknown metals, X and Z. The percent by mass of X and the percent by mass of

Aleksandr-060686 [28]

<u>Answer:</u> The additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X

<u>Explanation:</u>

To calculate the mole percent of a substance, we use the equation:

$\text{Mole percent of a substance}=\frac{\text{Moles of a substance}}{\text{Total moles}}\times 100$

Mass percent means that the mass of a substance is present in 100 grams of mixture

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We require the molar masses of Z and X to calculate the mole percent of Z and X respectively

Hence, the additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X

8 0

3 years ago

Cytotoxic t cells can attack target cells with which chemical weapons?

Aneli [31]

Answer:

secrete cytotoxic substance which triggers apoptosis of target cell.

Explanation:

Cytotoxic T cells have cell surface receptor which recognizes the antigen present on the receptor of target cell. This interaction initiates the process of killing of target cell.

After interaction cytotoxic t cell release cytotoxic substance called granzyme and perforin. Granzyme triggers apoptosis through the activation of caspases or by making the release of cytochrome c and activation of the apoptosome.

Perforin make pores in the cell and its action is similar to complement membrane attack complex. Therefore cytotoxic substances are released by Tc cells which trigger apoptosis of target cell.

4 0

3 years ago

A gas that was cooled to 200 Kelvin has a volume of 65.8 L. If its initial volume was 132.4 L, what was its initial temperature?

Mandarinka [93]

Answer:

Initial temperature, T1 = 99.4 Kelvin

Explanation:

<u>Given the following data;</u>

Initial volume, V1 = 65.8 Litres
Final temperature, T2 = 200 Kelvin
Final volume, V2 = 132.4 Litres

To find the initial temperature (T1), we would use Charles' law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles' law is given by the formula;

$\frac {V}{T} = K$

$\frac {V_{1}}{T_{1}} = \frac {V_{2}}{T_{2}}$

Making T1 as the subject formula, we have;

$T_{1} = \frac {V_{1}T_{2}}{V_{2}}$

Substituting the values into the formula, we have;

$T_{1} = \frac {65.8 * 200}{132.4}$

$T_{1} = \frac {13160}{132.4}$

<em>Initial temperature, T1 = 99.4 Kelvin</em>

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