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Vinil7 [7]
3 years ago
13

Which of the following is possible for aluminum to have a full outer shell?

Chemistry
2 answers:
lesya [120]3 years ago
8 0
B. Three are lost creating Al+3. Because atoms have and equal amount of Protons and Electons when neutral losing 3 electrons will create a positive Al ion Al+3
liubo4ka [24]3 years ago
4 0

The answer is; B.

This is called an aluminum cation. Aluminum forms bonds with anions in which it can donate its three valence electrons so it can achieve stable electron configuration. Stable electron configuration is having 8 electron in the outer shell. By donating its 3 outer valence electrons, the aluminium will have the more stable 2.8 electron configuration. The +3 means it has lost 3 electrons hence has 3 extra protons (that are not matched by an electron) in its nucleus (also indicating its valency).

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How many moles are in a 111.5 gram sample of sodium chloride, NaCl?
Katarina [22]

Answer: 1.91 moles

Explanation:

First you want to find the molar mass of NaCL

Na = 22.99g  Cl = 35.45g

22.99g + 35.45g = 54.44g

Then divide 111.5g by 54.44g and this will give you moles.

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The difference between all of them in the make-up of the R group.



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3 years ago
Into which two smaller groups are plants divided.
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5 0
3 years ago
Determine the AMOUNT OF NO2, LIMITING REACTANT, AND THE AMOUNT AND NAME OF EXCESS REACTANT.
zepelin [54]

Answer:

balanced equation mole ratio 5 2 mol NO/1 mol O2

10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2

20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO

actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2

Because the actual mole ratio of NO:O2 is larger than the balanced equation mole

ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.

Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO

0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO

Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2

Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N

Explanation:

3 0
2 years ago
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