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3 years ago

List three changes of state during which energy is absorbed

1 answer:

4 0

"Changes of state are physical changes. They occur when matter absorbs or loses energy. Processes in which matter changes between liquid and solid states are freezing and melting. Processes in which matter changes between liquid and gaseous states are vaporization, evaporation, and condensation."

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Three other application of Bernoulli's principle ?

Makovka662 [10]

<h2>Answer:</h2>

Bernoulli's Theorem in a general sense relates the weight, speed, and rise in a moving fluid (liquid or gas), the compressibility and consistency (internal grinding) of which are insignificant and the flood of which is predictable, or laminar.

(1): We can discover the speed of Efflux of a fluid.

This is given by v= sqrt (2gh), where the fluid is turning out from an opening in a vessel at profundity h from free fluid surface. This condition is known as Torricelli's hypothesis.

(2): Vena Contracta: The fluid stream from gap contracts at a separation minimal outside the opening to a neck, called Vena Contracta.

The territory of cross-segment of a fly is littler than a zone of opening. From this reality, we can discover the coefficient of withdrawal.

(3) : Bernoulli's standard is utilized in the development of Venturimeter, an instrument for estimation of measure of a stream of a fluid through a pipe.

7 0

3 years ago

What is the molality of a solution of 10 g NaOH in 500 g water? Molar mass NaOH = 40 g

umka2103 [35]

Explanation:

Moles of NaOH = 10g / (40g/mol) = 0.25mol.

0.25mol / 500g = 0.50mol / 1000g = 0.50mol/dm³.

The molarity is 0.50mol/dm³.

4 0

3 years ago

What is the total pressure exerted by the mixture of gases only products or products + reactants?

dedylja [7]

Total = products + reactants

3 0

3 years ago

A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc

Elan Coil [88]

Answer:

a. Moles of $NaOH$ = 0.001643 moles

b. 0.296 g

c. 0.3098 g

d. Not acceptable

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For $NaOH$ :

Molarity = 0.1052 M

Volume = 15.62 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.62×10⁻³ L

Thus, moles of $NaOH$ :

$Moles=0.1052 \times {15.62\times 10^{-3}}\ moles$

Moles of $NaOH$ = 0.001643 moles

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g

1.159 g of sample contains 0.296 g of acetylsalicylic acid

1.213 g of sample contains $\frac{0.296}{1.159}\times 1.213$ g of acetylsalicylic acid

Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg

d. Sample contains = 309.8 mg

Manufacturer claiming = 315 mg to 335 mg

Thus , it is not acceptable.

5 0

3 years ago

For the following reaction, 33.7 grams of bromine are allowed to react with 13.0 grams of chlorine gas.

Ira Lisetskai [31]

Explanation:

The reaction is given as;

Br2(g) + Cl2(g) ----> 2BrCl(g)

From the equation;

1 mol of Br2 reacts with 1 mol of Cl2

Converting the masses given to moles, using the formular;

Number of moles = Mass / Molar mass

Br2;

Number of moles = 33.7 g / 159.808 g/mol = 0.21088 mol

Cl2;

Number of moles = 13.0 g / 70.906 g/mol = 0.18334 mol

From the values;

0.18334 mol of Cl2 would react with 0.18334 mol of Br2 with an excess of 0.02754 mol of Br2

What is the maximum amount of bromine monochloride that can be formed? __________grams

1 mol of Cl2 produces 2 mol of Bromine Monochloride

0.18334 mol of Cl2 would produce x

Solving for x;

x = 0.18334 * 2 = 0.36668 mol

Converting to mass;

Mass = Number of moles * Molar mass = 0.36668 mol * 115.357 g/mol

Mass = 42.299 g

What is the FORMULA for the limiting reagent?

The limiting reagent is Cl2 as it determines the amount of product formed. The moment the reaction uses up Cl2, the reaction stops.

What amount of the excess reagent remains after the reaction is complete? __________grams

The excess reagent is Br2

The number of moles left is;

0.02754 mol of Br2

Converting to mass;

Mass = Number of moles * Molar mass = 0.02754 mol * 159.808 g/mol

Mass = 4.401 g

7 0

2 years ago