A + w = 300
a = w + 40
(w + 40) + w = 300
2w + 40 = 300
2w = 300 - 40
2w = 260
w = 260/2
w = 130 <=== cost of wooden bat
a = w + 40
a = 130 + 40
a = 170 <=== cost of aluminum bat
Answer:
18 is the answer to your question.
Answer:
x = 23
y = 110
Step-by-step explanation:
70 and 3x+1 are alternate exterior angles and that means they are equal
70 =3x+1
Subtract 1 from each side
69 = 3x
Divide by 3
69/3 =3x/3
23 =x
70 and y are same side exterior angles and that means they are supplementary ( add to 180)
70+y = 180
y = 180-70
y = 110
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation .
In this problem:
- The mean is of 660, hence .
- The standard deviation is of 90, hence .
- A sample of 100 is taken, hence .
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:
By the Central Limit Theorem
has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213