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ASHA 777 [7]
3 years ago
7

A right triangle has legs measuring 6 and 7 inches. What is the length of the hypotenuse?

Mathematics
1 answer:
Alchen [17]3 years ago
8 0

Answer:

5

Step-by-step explanation:

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Solving one step equations 1/4 a = 3
Pie

Answer:

a = 12

Step-by-step explanation:

\frac{1}{4} a = 3

Convert element into fraction : 3= 3/1

\frac{1a}{4}  =  \frac{3}{1}

Cross multiply

1a \times 1 = 4 \times 3 \\ a = 12

6 0
3 years ago
Farmer Ed has 9,500 meters of fencing,
Andreas93 [3]

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get:</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: </em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for x</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equation</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distribute</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y</em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y </em>

<em>Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y You can see that this is a parabola which opens down, meaning that the point of maximum area will be at the vertex, y = </em><em>- </em><em>b</em><em>/2a = -7500/[2(-2)] = 1875</em>

<em>/2a = -7500/[2(-2)] = 1875 </em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750</em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 </em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2</em>

<em>/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2 </em>

5 0
2 years ago
Together, Steve and Tom sold 79 raffle tickets for their school. Steve sold 13 more than twice as many raffle tickets as Tom. Ho
AysviL [449]
Tom sold 22 tickets and Steve sold 57 tickets here is the method

4 0
3 years ago
Is 1/4 a rational or irrational number
ycow [4]
Hi there!

1/4 is a rational number.
Any number that can be written as a fraction is a rational number.

~ Hope this helps you ~
6 0
3 years ago
Find The range and interquartile 45279.11, 5271. 04, 5309.73, 5363.38, 5409.72, 5444.74,  5603.46, 5695.39, 5871.96, 5972.35
dangina [55]

Answer:

40008 07 is the answer good luck :)

8 0
2 years ago
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