The answer is 15 in³.
The volume of the cone is:

where:
V₁ - the volume of the cone
r₁ - the radius of the cone
h₁ - the height of the cone
The volume of the cylinder is:

where:
V₂ - the volume of the cone
r₂ - the radius of the cone
h₂ - the height of the cone
Since <span>the cone fits exactly inside of the cylinder, they have the same radius and the height:
r</span>₁ = r₂
h₁ = h₂
Also:
V₁ = 5
Now, let's write two volume formulas together:

<span>

</span>
We can include V₂ into V₁:

⇒


Answer:
Angle D=162 P=74cm A=340sqcm
65 % ------------------ 23.4 items
100 % ----------------- x items
65 : 100 = 23.4 : x
65 x = 100 * 23.4
65 x = 2340
x = 2340 : 65
x = 36
Answer: there were 36 items on the test.
Answer: the answer is Triangles BCP and CDP are condruent
Step-by-step explanation: