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Natasha_Volkova [10]

3 years ago

7

What happens to matter when it reaches absolute zero?

2 answers:

vladimir2022 [97]3 years ago

4 0

Answer:

O C. Its particles vibrate slightly.

Explanation:

At absolute zero, atoms would occupy the lowest energy state.They move much less than at higher temperatures, but they still have small vibrations at absolute zero.

777dan777 [17]3 years ago

4 0

Answer:

The answer is B its particles have no kinetic energy

Explanation:

trust the big brain

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After a long night of cramming for a test, your college roommate hits his head forcefully against the wall of your room in despa

sweet [91]

Answer:

See the answer below

Explanation:

Newton's third law states that for every action, there will always be an opposing reaction of equal magnitude to the action.

<em>Hence, the wall will exert an equal opposing force to the head and the roommate will feel this opposing force as pains and/or headache. </em>

3 0

3 years ago

An object takes 2.8 years to orbit the Sun. What is its average distance (in AU) from the Sun?

Inessa05 [86]

answer look it up

Explanation:https://www.chegg.com/homework-help/questions-and-answers/takes-planet-28-years-orbit-sun-long-years-take-planet-go-way-around-sky-q29849397

5 0

3 years ago

Please help me ..im begging you

Deffense [45]

Explanation:

let's assume that:

v1= 600ml=0,6l

T1=27°C= 300K

p1=700mmHG=93326Pa

T2=-20°C=253K

p2=500mmHg=66661

V2=?

p1V1/T1=p2V2/T2 => V2=p1V1T2/p2

V2= 93326*0,6*253/66661

V2=212,52l

5 0

3 years ago

You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that

loris [4]

Questions Diagram is attached below

Answer:

$T=2.08s$

Explanation:

From the question we are told that:

Speed of Train $V=3.0m.s$

Angle $\theta=12\textdegree$

Height of window $h_w=0.90m$

Width of window $w_w=2.0m$

The Horizontal distance between B and A from Trigonometric Laws is mathematically given by

$b=\frac{0.9}{tan12}$

$b=4.23$

Therefore

Distance from A-A

$d_a=2.0+4.23$

$d_a=6.23$

Therefore

Time Required to travel trough d is mathematically given as

$T=\frac{d_a}{v}$

$T=\frac{6.23}{3}$

$T=2.08s$

5 0

3 years ago

What is the total energy q released in a single fusion reaction event for the equation given in the problem introduction? use c2

kkurt [141]

Answer:

$4.3\cdot 10^{-12} J$

Explanation:

The fusion reaction in this problem is

$4^1_1H \rightarrow ^4_2He +2e^+$

The total energy released in the fusion reaction is given by

$\Delta E = c^2 \Delta m$

where

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\Delta m$ is the mass defect, which is the mass difference between the mass of the reactants and the mass of the products

For this fusion reaction we have:

$m(^1_1H)=1.007825u$ is the mass of one nucleus of hydrogen

$m(^4_2 He)=4.002603u$ is the mass of one nucleus of helium

So the mass defect is:

$\Delta m =4m(^1_1 H)-m(^4_2 He)=4(1.007825u)-4.002603u=0.028697u$

The conversion factor between atomic mass units and kilograms is

$1u=1.66054\cdot 10^{-27}kg$

So the mass defect is

$\Delta m =(0.028697)(1.66054\cdot 10^{-27})=4.765\cdot 10^{-29}kg$

And so, the energy released is:

$\Delta E=(3.0\cdot 10^8)^2(4.765\cdot 10^{-29})=4.3\cdot 10^{-12} J$

6 0

3 years ago