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attashe74 [19]
3 years ago
8

You are on a train that is traveling at 3.0 m/s along a level straight track. Very near and parallel to the track is a wall that

slopes upward at a 12 angle with the horizontal. As you face the window (0.90 m high, 2.0 m wide) in your compartment, the train is moving to the left, as the drawing indicates. The top edge of the wall first appears at window corner A and eventually disappears at window corner B. How much time passes between appearance and disappearance of the upper edge of the wall
Physics
1 answer:
loris [4]3 years ago
5 0

Questions Diagram is attached below

Answer:

T=2.08s

Explanation:

From the question we are told that:

Speed of Train V=3.0m.s

Angle \theta=12\textdegree

Height of window h_w=0.90m

Width of window w_w=2.0m

The Horizontal distance between B and A from Trigonometric Laws is mathematically given by

 b=\frac{0.9}{tan12}

 b=4.23

Therefore

Distance from A-A

 d_a=2.0+4.23

 d_a=6.23

Therefore

Time Required to travel trough d is mathematically given as

 T=\frac{d_a}{v}

 T=\frac{6.23}{3}

 T=2.08s

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Lunna [17]

Answer:

The change in power is 4400 W.

Explanation:

Given that,

Power = 10 kW

Speed = 10 m/s

Increases speed = 12 m/s

Given equation is,

F=kv

We know that,

The power is,

P=Fv

Put the value of F into the formula

P=(kv)v

P=kv^2

P\propto v^2

We need to calculate the new power

Using formula for power

\dfrac{P}{P'}=\dfrac{v^2}{v'^2}

Put the value into the formula

\dfrac{10}{P'}=(\dfrac{10}{12})^2

P'=(\dfrac{12}{10})^2\times10

P'=14.4\ kW

We need to calculate the change in power

Using formula of change in power

\Delta P=P'-P

Put the value into the formula

\Delta P=14.4-10

\Delta P=4.4\ kW

\Delta P=4.4\times1000

\Delta P=4400\ W

Hence, The change in power is 4400 W.

6 0
4 years ago
Two children of mass 27 kg and 51 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the c
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Answer:

2.62 m

Explanation:

Let the small child sit at a distance x from the pivot.

The distance of big child from the pivot is 4 - x .

By using the concept of moments.

Clockwise moments = anticlockwise moments

27 x = 51 ( 4 - x )

27 x = 204 - 51 x

78 x = 204

x = 2.62 m

8 0
3 years ago
the temperature of a body fell from 100°c to 50°c in 10 minutes. the surrounding temperature was 20°c. what is the temperature a
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Answer:

The temperature is 10 c

4 0
3 years ago
A proton is a subatomic particle that carries a ___________ charge
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The answer would be a positive charge

4 0
3 years ago
How much work in joules is required to lift a 23 kg box up from the ground to your waist that is 1.0 meters high, carry it 6 met
PSYCHO15rus [73]

Answer:

2682

Explanation:

Work done is given by :

Work = Force x distance

         =  mg x d

So, work done in lifting the box of 23 kg up to my waist of 1 m high is :

W = mg x d

   = 23 x 9.18 x 1

   = 211.14

Now work done carrying the box horizontally 6 meters across the room is

W = mg x d

   = 23 x 9.18 x 6

   = 1266.84

Work done in placing the box on the shelf that is 5.7 m above the ground is

W = mg x d

   = 23 x 9.18 x 5.7

   = 1203.49

So the total work done is = 211.14 + 1266.84 + 1203.49

                                          = 2681.47

                                          = 2682 (rounding off)

5 0
3 years ago
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