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3 years ago

An object takes 2.8 years to orbit the Sun. What is its average distance (in AU) from the Sun?

Physics

1 answer:

Inessa05 [86]3 years ago

5 0

answer look it up

Explanation:https://www.chegg.com/homework-help/questions-and-answers/takes-planet-28-years-orbit-sun-long-years-take-planet-go-way-around-sky-q29849397

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a 91.5 kg football player running east at 3.73 m/s tackles a 63.5 kg player running east at 3.09 m/s. what is their velocity aft

Lesechka [4]

The final velocity is 3.47 m/s east

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the two players before and after the collision must be conserved:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 91.5 kg$ is the mass of the first player

$u_1 = 3.73 m/s$ is the initial velocity of the first player (we take east as positive direction)

$m_2 = 63.5 kg$ is the mass of the second player

$u_2 = 3.09 m/s$ is the initial velocity of the second player

$v$ is their final combined velocity after the collision

Re-arranging the equation and substituting the values, we find:

$v = \frac{m_1 u_1+m_2 u_2}{m_1+m_2}=\frac{(91.5)(3.73)+(63.5)(3.09)}{91.5+63.5}=3.47 m/s$

So, their velocity afterwards is 3.47 m/s east.

Learn more about momentum:

brainly.com/question/7973509

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#LearnwithBrainly

6 0

3 years ago

When an object such as a plastic comb is charged by rubbing it with a cloth, the net charge is typically a few microcoulombs. If

masya89 [10]

The concept required to solve this problem is quantization of charge.

First the number of electrons will be calculated and then the total mass of the charge.

With these data it will be possible to calculate the percentage of load in the mass.

$Q= ne$

Here Q is the charge, n is the number of electrons and e is the charge on the electron

$n = \frac{Q}{e}$

Replacing,

$n = \frac{4*10^{-6}C}{1.6*10^{-19}}$

$n = 2.5 * 10^{13}77$

According to the quantization of charge the charge is defined as product of the number of electron and the charge on the electron

The total mass of the charge is

$m= nm_e$

Here,

m = Mass of the charge

n = Number of electrons

$m_e$ = Mass of the electron

$\text{Percentage change} = \frac{nm_e}{M}*100$

Replacing we have

$\text{Percentage change} = \frac{(2.5*10^13)(9.1*10^{-28})}{33}*100$

$\text{Percentage change} = 6.9*10^{-14} \%$

6 0

4 years ago

Which material would you take, steel or bricks/stone to design a bridge. Why? ( Question related to poisson's ratio)

Ann [662]

i would choose steel because the steel used for normal construction have several hundred Mega Pascal strength. one of the special feature of steel is its ductility. it is the deformation capability before the final breakage.

8 0

4 years ago

For a home sound system, two small speakers are located so that one is 52 cm closer to the listener than the other. For what val

Veseljchak [2.6K]

We want a sound wave with a wavelength of 0.52 meters or a natural fraction thereof. We'll work in MKS.

w = 0.52/n

That's length. We have speed 344 meters/second so w corresponds to a frequency of

f = 344 / w = n (344/.52)

f = 661.5 n Hertz

I don't really agree with how they're saying it, but all the fundamental talk is probably trying to tell us n=1,

Answer: 661.5 Hertz

Any multiple of that will also produce constructive interference; we can go to about n=30 before we're out of the audio range.

7 0

3 years ago

A student is late and running to class. A hall monitor tells them to slow down, so the student slows to a walking speed of 1.4 m

sergey [27]

Answer:

8.9m/s

Explanation:

Final velocity = initial velocity + acceleration *time

Vf=vi+at

Vf=1.4 m/s

Vi=?

A=-2.5m/s^2

T=3

1.4m/s=vi+(-2.5m/s^2)(3s)

Vi=8.9m/s

7 0

3 years ago