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3 years ago

5(b+6) - 3(?????) = 2b

Mathematics

2 answers:

katen-ka-za [31]3 years ago

8 0

Answer:

(b+10)

Step-by-step explanation:

I think that's the answer

strojnjashka [21]3 years ago

8 0

Step-by-step explanation:

it will ( b +10) hope it helps

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5) Naomi is sewing some clothing. She has 53 yards of fabric to use. She

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The inequality that represents the number of each type of fabric that Naomi has is:

$9x+16y \leq 53$

Let the number of short-sleeved shirts she made be x

Let the number of long-sleeved shirts she made be y

Length of clothes used to make a short-sleeved shirt = 9 yards

Length of clothes used to make a long-sleeved shirt = 16 yards

Length of short-sleeved shirts made = 9x

Length of long-sleeved shirts made = 16y

Total length of fabric used = 53 yards

The inequality that represents the number of each type of fabric that Naomi has is:

$9x+16y \leq 53$

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3 years ago

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The logarithm of a number to the base V2 is k. What is its logarithm to the base 2v2 ?

kakasveta [241]

Answer:

$log_{2\sqrt 2} X = \frac{1}{3}k$

Step-by-step explanation:

Given

Let the number be X

From the first statement, we have:

$log_{\sqrt 2} X = k$

Required

Find $log_{2\sqrt 2} X$

$log_{\sqrt 2} X = k$

using the following law of logarithm

$log_ab = n, b=a^n$

So:

$log_{\sqrt 2} X = k$

$X = \sqrt{2}^k$

Substitute: $X = \sqrt{2}^k$ in $log_{2\sqrt 2} X$

$log_{2\sqrt 2} X = log_{2\sqrt 2} ( \sqrt{2}^k)$

$log_{2\sqrt 2} X = klog_{2\sqrt 2} \sqrt{2}$

Apply the following law:

$log_ab = \frac{log\ b}{log\ a}$

$log_{2\sqrt 2} X = k\frac{log\ \sqrt 2}{log\ {2\sqrt 2}}$

Express the square roots as power

$log_{2\sqrt 2} X = k\frac{log\ 2^\frac{1}{2}}{log\ {2 * 2^\frac{1}{2}}}$

$log_{2\sqrt 2} X = k\frac{log\ 2^\frac{1}{2}}{log\ {2^\frac{3}{2}}}$

using the following law of logarithm

$log_ab = n, b=a^n$

$log_{2\sqrt 2} X = k\frac{\frac{1}{2}log\ 2}{\frac{3}{2}log\ 2}}$

$log_{2\sqrt 2} X = k\frac{\frac{1}{2}}{\frac{3}{2}}}$

Rewrite as:

$log_{2\sqrt 2} X = k * \frac{1}{2} \div\frac{3}{2}$

$log_{2\sqrt 2} X = k * \frac{1}{2} *\frac{2}{3}$

$log_{2\sqrt 2} X = k * \frac{1}{1} *\frac{1}{3}$

$log_{2\sqrt 2} X = \frac{1}{3}k$

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I belive it is 28
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5(b+6) - 3(?????) = 2b​

5(b+6) - 3(?????) = 2b