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3 years ago

At 6 AM the temperature read -17 F by noon it had risen by 23 F. Find the new temperature

Mathematics

1 answer:

11111nata11111 [884]3 years ago

4 0

Answer:

6 F

Step-by-step explanation:

We want to find the temperature difference

Given that the initial temperature read minus 17 F

And the new temperature is increased by 23 F

The new temperature is

=-17+23= 6 F

Therefore the new temperature is 6F

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given that sin theta= 1/4, 0 is less than theta but less than pi/2, what is the exact value of cos theta

lapo4ka [179]

Answer:

$\cos{\theta} = \frac{\sqrt{15}}{4}$

Step-by-step explanation:

For any angle $\theta$ , we have that:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

Quadrant:

$0 \leq \theta \leq \frac{\pi}{2}$ means that $\theta$ is in the first quadrant. This means that both the sine and the cosine have positive values.

Find the cosine:

$(\sin{\theta})^{2} + (\cos{\theta})^{2} = 1$

$(\frac{1}{4})^{2} + (\cos{\theta})^{2} = 1$

$\frac{1}{16} + (\cos{\theta})^{2} = 1$

$(\cos{\theta})^{2} = 1 - \frac{1}{16}$

$(\cos{\theta})^{2} = \frac{16-1}{16}$

$(\cos{\theta})^{2} = \frac{15}{16}$

$\cos{\theta} = \pm \sqrt{\frac{15}{16}}$

Since the angle is in the first quadrant, the cosine is positive.

$\cos{\theta} = \frac{\sqrt{15}}{4}$

3 0

3 years ago

Write this number in standard form. 300+80+0.9+0.06+0.001

Lina20 [59]

Hey there! I'm happy to help!

First, let's add the hundreds and the tens.

300+80=380

We see that there is nothing in the ones place, so we keep our ones place 0 and we move onto adding the tenths.

380+0.9=380.9

We add the hundredths.

380.9+0.06=380.96

And finally, we add the thousandths.

380.96+0.001=380.961

Therefore, this number in standard form is 380.961.

Have a wonderful day! :D

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Step-by-step explanation:

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zimovet [89]

Answer:

B. 51

Step-by-step explanation:

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Simplify the expression (2^3)^-2

snow_lady [41]

1/64

2^3 = 8

8^-2 = 1/64

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