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diamong [38]
3 years ago
7

I need help with this one please​

Mathematics
1 answer:
Zanzabum3 years ago
3 0

Answer: Dealership 4: he would pay $40.33

Step-by-step explanation: I used a calculator, so if you have 1/3 you put 1 divided by 3 in your calculator and right that down somewhere completely

Then, you divide $121 dollars by the number you got for 1 divided by 3 and then multiply it by 121 and should get 40.3333333333 but you round to the nearest tenth so it would by 40.33

1÷3= 0.33333333333

121×0.33333333333= 40.3333333333

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What is the y-intercept of the exponential function? y=2(3)^x
ValentinkaMS [17]

Answer:

( 0 , 2 )

Step-by-step explanation:

To find the x-intercept, substitute in 0 for y and solve for x . To find the y-intercept, substitute in 0 for x and solve for y .

x-intercept(s): None

y-intercept(s): ( 0 , 2 )

3 0
3 years ago
The value of y varies directly with x, and y = 343 when x = 49. find y when x = 8.
Natasha_Volkova [10]

The value of y is 56 when x = 8.

Given

y = 343 when x = 49

Value of y varies directly with x

Therefore, y ∝ x

We can write the equation with a constant 'k'

y = kx

When y = 343 and x = 49

343 = k × 49

k = 343/49

k = 7

When x = 8,

y = kx

y = 7 × 8

y = 56

The value of y is 56 when x = 8.

Find out more information about value of y here

brainly.com/question/1907608

#SPJ4

5 0
2 years ago
How much is 3 1/2 pounds writtten as a combination of whole pounds and whole ounces? explain how you found your answer
a_sh-v [17]
1 lb = 16 oz

3 1/2 (or 3.5)lbs = 3.5(16) = 56 oz which equals : 2 lbs and 24 oz or 3 lbs and 8 oz or 1 lb and 40 oz
6 0
3 years ago
1. Consider the population model dP dt = 0.2P 1 − P 135 , where P(t) is the population at time t. (a) For what values of P is th
Kryger [21]

Answer:

a

  P = 0  OR  P = 135

b

P > 0 and P < 135

OR

P > 0 and P < 135

c

Generally the carrying capacity is can be defined as the highest amount of population and environment can support for an unlimited duration or time period

d

P = 67.5

Step-by-step explanation:

From the question we are told that

The population model is \frac{dP}{dt}  =  0.2P(1 - \frac{P}{135} )

Generally at equilibrium

\frac{dP}{dt} = 0

So

0.2P = 0

=> P = 0

Or

(1 - \frac{P}{135} ) = 0

=> P = 135

Thus at equilibrium P = 0 or P = 135

Generally when the population is increasing we have that

\frac{dP}{dt} > 0

So

0.2P > 0

=> P > 0

and

(1 - \frac{P}{135} ) > 0

P < 135

Now when the first value of P i.e P< 0 for \frac{dP}{dt} > 0

P_2 > 135

So when population increasing the values of P are

P > 0 and P < 135

OR

P > 0 and P < 135

So to obtain initial values of P where the population converge to the carrying capacity as t \to [\infty]

The rate equation can be represented as

\frac{dP}{dt}  =  \frac{1}{5}P (1 - \frac{P}{135} )

So we will differentiate the equation again we have that

\frac{d^2 P}{dt^2} = \frac{(1 - \frac{P}{135} )}{5}  - \frac{P}{675}

Now as  t \to [\infty]

\frac{d^2 P}{dt^2} \to  0

So

   \frac{(1 - \frac{P}{135} )}{5}  - \frac{P}{675} = 0      

=>    \frac{(1 - \frac{P}{135} )}{5}   =  \frac{P}{675}

=> P = 67.5

5 0
3 years ago
Which of the following describe -1 4/6? Select all that apply.
artcher [175]

Answer:

rational number

Step-by-step explanation:

as the denominator is not zero

4 0
3 years ago
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