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Aleonysh [2.5K]
3 years ago
12

SOS HELP ME

Physics
1 answer:
Dafna1 [17]3 years ago
5 0

Answer:

Angle Vy Vy^2/(2*g)

25         6.3    2.02

30          7.5  2.87

45         10.6 5.73

50         11.5 6.75

65         13.6 9.44

70         14.1 10.1

Vy = vertical velocity = V sin theta

2 g H = Vy^2      since the final velocity is zero

H = Vy^2 / (2 * g)

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A laser beam is incident at an angle of 30.0° from the vertical onto a solution of corn syrup in water. The beam is refracted to
dimaraw [331]

Answer with Explanation:

We are given that

Angle of incidence,i=30^{\circ}

Angle of refraction,r=19.24^{\circ}

a.Refractive index of air,n_1=1

We know that

n_2sinr=n_1sini

n_2=\frac{n_1sin i}{sin r}=\frac{sin30}{sin19.24}=1.517

b.Wavelength of red light in vacuum,\lambda=632.8nm=632.8\times 10^{-9} m

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Where c=3\times 10^8 m/s

Frequency,\nu=4.74\times 10^{14}Hz

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3 years ago
In order for a color to be seen by a human, the light must be
ololo11 [35]
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A child has an ear canal that is 1.3 cm long. Assume the speed of sound is v = 344 m/s.
kap26 [50]

Answer:

The  frequencies are (f, f_1) =  (6615.4 \ Hz , 19846.2\ Hz)

Explanation:

From the question we are told that

  The  length of the ear canal is  l = 1.3 \ cm  =\frac{1.3}{100}  =  0.013 \ m

   The  speed of sound is assumed to be  v_s  =  344 \ m/s

Now  taking look at a typical  ear canal  we see that we assume it is  a  closed pipe

   Now the fundamental harmonics for the pipe(ear canal) is mathematically represented as

            f = \frac{v_s}{4 * l }

 substituting values  

          f = \frac{344}{4 * 0.013 }

         f = 6615.4 \ Hz

Also the the second harmonic for the pipe (ear canal) is mathematically represented as

        f_1 =  \frac{3v_s}{4 * l}

 substituting values  

       f_1 =  \frac{3 *  344}{4 * 0.013}

       f_1 =   19846.2 \ Hz

Given that sound would be loudest in the pipe at the frequency, it implies that the child  will have an increased audible sensitivity at this  frequencies

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Answer:

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