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ohaa [14]
3 years ago
15

Two cars are heading towards each other but are 12 km apart. one car is going 70 km/hr, and the other is going 50 km/hr. how muc

h time do they have before they collide head on?
Physics
1 answer:
vova2212 [387]3 years ago
3 0
<span>12-50t=70t, t= 0.1h = 6 minutes.</span>
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Besides gravity, what factor keeps the moon and Earth in orbit?
Gelneren [198K]

Answer:

(D) Inertia

Explanation:

Inertia words with Gravity to keep the Moon, Earth and Sun All in Orbit!

                                                      <em>-Aslina</em>

7 0
3 years ago
Just a thought
Olin [163]

Answer:

Explanation:

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6 0
2 years ago
The wind is blowing horizontally at 30 m / s in a storm at P o , 20°C toward a wall, where it comes to a stop (stagnation) and l
aleksklad [387]

Answer:

 To=20.44 °C    

Explanation:

Given that

Velocity , v= 30 m/s

Temperature , T= 20°C

We know that specific heat capacity for air ,Cp=1.005 kJ/kg.K

By using energy conservation ,the stagnation temperature is given as

T_0=T+\dfrac{v^2}{2C_p}

Now by putting the values in the above equation we get

T_0=(20+273)+\dfrac{30^2}{2\times 1.005\times 1000}\ K

To= 293.44 K

To= 293.44 - 273 °C

To=20.44 °C

Therefore the stagnation temperature will be 20.44 °C.

3 0
3 years ago
The surface tension of water is 7.28 ✕ 10−2 J/m2 at 20°C. Predict whether the surface tension of octane would be higher or lower
qaws [65]

Explanation:

It is known that octane is a hydrocarbon and London dispersion forces are the main intermolecular forces which are present in it.

Whereas water molecules tend to form hydrogen bonding forces which are actually much stronger than dipole-dipole interactions. This means that more energy is necessary to separate water molecules from one another than to separate octane molecules from one another.

Hence, we can conclude that surface tension of octane is expected to be lower than that of water when the two are considered at the same temperature.

7 0
3 years ago
An infinite line of charge with charge density λ1 = 0.6 μC/cm is aligned with the y-axis.
Ganezh [65]

Answer:

1440 × 10⁴ N/C

Explanation:

Data provided in the question:

Charge density λ1 = 0.6 μC/cm = 6 × 10⁻⁵ C/m

a = 7.5 cm = 0.075 m

Now,

Electric field due to a line charge at a distance 'a' is given as:

Ex(P) = \frac{\lambda}{2\pi\epsilon_0a}

also,

we know

\frac{1}{4\pi\epsilon_0} = 9 × 10⁹ Nm²/C²

Thus,

we have

Ex(P) = \frac{2}{2}\times\frac{\lambda}{2\pi\epsilon_0a}=\frac{2\lambda}{4\pi\epsilon_0a}

therefore,

Ex(P) = \frac{2\times6\times10^{-5}\times9\times10^9}{0.075}

= 1440 × 10⁴ N/C

8 0
3 years ago
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