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Paul [167]
3 years ago
13

What is the mean of 2 4 5 6 8

Mathematics
2 answers:
ladessa [460]3 years ago
5 0
The mean just means (pun) the average of a data set. You add all the numbers and divide by how many are present

(2+4+5+6+8) / 5 or 25/5 aka 5

Hope this helps ya
Sergio039 [100]3 years ago
3 0

Answer:

The mean of <u>2 4 6 8</u> is 6

bc Means is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

Step-by-step explanation:

Hope this helps :)

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What is the center and radius of the circle? *<br> x^2+ y^2+ 4y + 4 = 36
Rina8888 [55]

Answer:

(0, - 2 ), r = 6

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Rearrange the given equation collecting the terms in y together, that is

x² + y² + 4y + 4 = 36 ( subtract 4 from both sides )

x² + y² + 4y = 32

Use the method of completing the square on the y- terms

add ( half the coefficient of the y- term)² to both sides

x² + y² + 2(2)y + 4 = 32 + 4

x² + (y + 2)² = 36 ← in standard form

with (h, k ) = (0, - 2 ) and r² = 36, thus

centre = (0, - 2 ) and r = \sqrt{36} = 6

8 0
2 years ago
IS THIS CORRECT? THANK YOU
galina1969 [7]

Answer:

yes its correct

Step-by-step explanation:

6 0
3 years ago
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GalinKa [24]

Answer:

He spent 144.42   and he got back 55.58

Step-by-step explanation:

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3 years ago
Which pair of triangles can be used to show that the slope of line a is the same anywhere along the line?
aalyn [17]

Answer:

C

Step-by-step explanation:

The pair of triangles in option C (image attached below) shows that the slope of line a is the same anywhere on the line.

Let's check it out:

Slope = rise/run

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Rise = 3.5

Run = 4.5

Slope = 3.5/4.5 ≈ 0.8

✔️For the second upper traingle:

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Slope = 4/5 = 0.8

Therefore, it shows that the slope of the line is the same anywhere along the line of the graph.

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they needed weapons for fighting the opponent

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