A uniform beam is 2m long, has a mass 100 kg, and it is supported at its center by a triangular support. the beam is balanced. M
1 answer:
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Answer:
6 V
Explanation:
In a circuit, the relationship between voltage, current and resistance is given by Ohm's law:
where
V is the voltage
R is the resistance
I is the current
In this circuit, we have
is the resistance
I = 0.500 A
so we can find the voltage of the battery by using Ohm's law:
Answer:
The spring constant is 4159.02 N/m.
Explanation:
Given:
Mass of the ball (m) = 79.5 g = 0.0795 kg [1 g = 0.001 kg]
Height of the ball above spring (h) = 51.3 cm = 0.513 m [1 cm = 0.01 m]
Compression in the spring (x) = 4.57537 cm = 0.0457537 m
Total vertical displacement of the ball is equal to the sum of height above spring and compression of the spring. So,
Total vertical height (h+x) = 51.3 cm + 4.57537 cm = 55.87537 cm = 0.5587537 m
Now, as per energy conservation, the total energy of the ball at any position is always a constant.
So, energy possessed by the ball the highest point is equal to the energy possessed by the ball at the lowest point.
Energy at the highest point is due to gravitational potential energy only and energy at the lowest point is due to elastic potential energy only.
So, GPE = EPE
Here 'k' is the spring constant.
Now, plug in all the values and solve for 'k'. This gives,
Therefore, the spring constant is 4159.02 N/m.