Answer:
its surface temperature = 54.84 ° C
Explanation:
The density of aluminium = 2700 kg/m ³
Heat capacity = 897 J/Kg.K
radius of the sphere (r) = 0.081029 m
= 25 °C
= 124.978 °C
time (t) = 767.276 s
Using the formula :
where.
Replacing our values ;we have:
T ≅ 54.84 ° C
Therefore, its surface temperature = 54.84 ° C
Answer:
The distance between their eye and the ceiling is 33.06 m.
Explanation:
Given that,
The ceiling of a large symphony hall is covered with acoustic tiles which have small holes that are 4.35 mm center to center, D = 4.35 mm
Diameter of the eye of pupil, d = 5.1 mm
Wavelength,
We need to find the distance between their eye and the ceiling. Using Rayleigh criteria, we get the distance as follows :
So, the distance between their eye and the ceiling is 33.06 m.
Answer:
Approximately (assuming that the projectile was launched at angle of
above the horizon.)
Explanation:
Initial vertical component of velocity:
.
The question assumed that there is no drag on this projectile. Additionally, the altitude of this projectile just before landing is the same as the altitude
at which this projectile was launched:
.
Hence, the initial vertical velocity of this projectile would be the exact opposite of the vertical velocity of this projectile right before landing. Since the initial vertical velocity is (upwards,) the vertical velocity right before landing would be
(downwards.) The change in vertical velocity is:
.
Since there is no drag on this projectile, the vertical acceleration of this projectile would be . In other words,
.
Hence, the time it takes to achieve a (vertical) velocity change of would be:
.
Hence, this projectile would be in the air for approximately .