Answer:
The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction
Explanation:
Inelastic Collision
Given data
mass of glider A m1= 0.125kg
initial velocity u1=0
final velocity v1= 0.600 m/s
mass of glider B m2= 0.375kg
initial velocity u2=0
final velocity v2=?
We know that the expression for the conservation of momentum is given as
m1u1+m2u2=m1v1+m2v2
since u1=u2=u=0m/s
u(m1+m2)=m1v1+m2v2
substituting we have
0(0.125+0.0375)=0.125*0.6+0.375*v2
0=0.075+0.375v2
0.375v2=-0.075
v2=-0.075/0.375
v2=-0.2m/s
The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction
Answer:
θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²
Explanation:
This is an angular kinematic exercise the equation for the angular position
the particle A
θ = θ₀ + ω₀ t + ½ α t²
They say for the particle B
w₀B = ½ w₀
αB = 2 α
In addition, the particle begins at a time t_1 after particle A, in order to use the same timer, we must subtract this time from the initial
t´ = t - t_1
l
et's write the equation of particle B
θ = θ₀ + w₀B t´ + ½ αB t´2
replace
θ = θ₀ + ½ w₀ (t -t_1) + ½ 2α (t -t_1)²
θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²
The average kinetic energy of the particles is higher in the hot tea, so it also has greater thermal energy then the cold tea.
Answer:
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