Answer:
the velocity of the bullet-wood system after the collision is 2.48 m/s
Explanation:
Given;
mass of the bullet, m₀ = 20 g = 0.02 kg
velocity of the bullet, v₀ = 250 m/s
mass of the wood, m₁ = 2 kg
velocity of the wood, v₁ = 0
Let the velocity of the bullet-wood system after collision = v
Apply the principle of conservation of linear momentum to calculate the final velocity of the system;
Initial momentum = final momentum
m₀v₀ + m₁v₁ = v(m₀ + m₁)
0.02 x 250 + 2 x 0 = v(2 + 0.02)
5 + 0 = v(2.02)
5 = 2.02v
v = 5/2.02
v = 2.48 m/s
Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s
6^2 + 8^2 = 36 + 64 = 100
sqrt(100) = 10 m/s northwest
That ratio is the efficiency of whatever the power went into and came out of. There's no reason the efficiency has to be expressed as a percentage.
Answer:
near a flame and a hot plate
Explanation:
In a series circuit . . .
There is only one path for current to take.
All the way from one terminal of the power supply, through all of
the lights, computers, vending machines, air conditioners and
everything else in the building, to the other terminal of the electric
supply. One path !
So the current for EVERY device has to flow through ALL of them,
because that's the only path there is.
If any ONE device in the building was turned off, burned out, or
unplugged from the outlet, then there would be NO PATH for the
current, and everything in the building would lose power !
Not a very convenient way to operate a house or a building.