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babunello [35]
3 years ago
9

A person walked 30.0 m east and then 100.0 m north. Add these two vectors to get the magnitude of the vector sum of the two move

ments.
Physics
1 answer:
lakkis [162]3 years ago
7 0

Answer:

D = 104.4 m

Explanation:

We are given two displacement vectors. One in north direction other in east direction. We know that north and east directions are perpendicular to each other. Hence, the displacements vectors are also perpendicular to each other. Therefore, there resultant can be found by using Pythagora's Theorem like rectangular components method.

D = √(Dₓ² + Dy²)

where,

D = Magnitude of vector sum of both displacements = ?

Dₓ = Magnitude of Displacement Vector in east direction = 30 m

Dy = Magnitude of Displacement Vector in North Direction = 100 m

Therefore,

D = √[(30 m)² + (100 m)²]

<u>D = 104.4 m</u>

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Answer:

the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

Given;

mass of the bullet, m₀ = 20 g = 0.02 kg

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mass of the wood, m₁ = 2 kg

velocity of the wood, v₁ = 0

Let the velocity of the bullet-wood system after collision = v

Apply the principle of conservation of linear momentum to calculate the final velocity of the system;

Initial momentum = final momentum

m₀v₀ + m₁v₁ = v(m₀ + m₁)

0.02 x 250  + 2 x 0    =    v(2  + 0.02)

5 + 0 = v(2.02)

5 = 2.02v

v = 5/2.02

v = 2.48 m/s

Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s

6 0
3 years ago
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