Answer:
10.9 s
Explanation:
Given:
Δx = 367 m
v₀ = 0 m/s
a = 6.2 m/s²
Find: t
Δx = v₀ t + ½ at²
367 m = (0 m/s) t + ½ (6.2 m/s²) t²
t ≈ 10.9 s
light, water, carbon dioxide
Explanation:
c02 , h20 and light
Answer:
a)1.51*10^-22joules b) 1.89*10^-7m
Explanation:
Work done to stop the proton = the kinetic energy of the proton = 1/2 mv^2 = 1/2* 1.67*10^-27* 425*425 = 1.51* 10 ^ -22 joules
b) net force acting to stop the proton = 8.01*10^-16
Work done needed to stop the proton = net force acting opposite the motion * distance
Distance covered = need work done/ net force
Distance = 1.51*10^-22/8.01*10^-16= 1.89*10^-7m
Answer:
0
Explanation:
It’s before the projectile was fired, so nothing has happened yet.
