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Lesechka [4]
2 years ago
7

What is the current in the 10.0 , resistor?

Physics
2 answers:
In-s [12.5K]2 years ago
5 0

Answer:

B. 12.0A

Explanation:

The circuit shown in the image is a parallel circuit which mean that the voltage of the source is equal across each resistance in the circuit because they are directly connected to the terminals of the voltage source.

The voltage across the 10 Ohms resistor is 120V

So, let's proceed to calculate the current

By using Ohm's Law

I=\frac{V}{R} \\I= \frac{120.0V}{10.0Ohm} \\I= 12.0A

12A is the amount of current flowing through the 10 ohms resistor.

olga nikolaevna [1]2 years ago
4 0

Current = (voltage) / (resistance)

The ends of the 10-ohm resistor are connected directly to both terminals of the battery.  

So the voltage across the resistor is the voltage of the battery ... 120 V.  None of that other stuff in the circuit has any effect on it.

Current = (120 V) / (10 ohms)

<em>Current = 12 A .  (B)</em>

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c) O

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a) since charge -Q is moved from A to B, this implies that sphere A is negatively charged. The two spheres are now negatively charged and will repel themselves.

b) initial force will be -q(-Q)/d2

Adding extra charge -Q will cause change on B to become -2Q

The new force will be - 2Q(-q)/d2

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C) if B is neutralized, the net charge becomes 0 and there will be no force on it.

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2 years ago
A satellite is in a circular orbit 8200 km above the Earth’s surface; i.e., it moves on a circular path under the influence of n
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5.23km/s

Explanation:

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Radius of Earth = 6.37 * 10^6 m

Altitude of Satellite = 8200km = 8200 * 10³m = 8.2 * 10^6 m

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For a satellite to remain in circular orbit, then it means the acceleration of gravity must be exact as the centripetal acceleration.

Centripetal Acceleration = V²/R

So, Acceleration of Gravity (A)= Centripetal Acceleration = V²/R

Make V the subject of formula

A = V²/R

V² = AR

V = √AR

Where R = (radius of earth) + (altitude of satellite)

R = 6.37 * 10^6 + 8.2 * 10^6

R = 14.57 * 10^6m

A = 1.87965m/s²

V = √(1.87965 * 14.57x10^6)

V = √27386500.5

V = 5233.211299001789

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What is the magnitude of the resultant vector? Round
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Mention one life application on density ​
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2 years ago
Ocean waves of wavelength 26 m are moving directly toward a concrete barrier wall at 4.0 m/s . The waves reflect from the wall,
Genrish500 [490]

Answer:

a) the distance between her and the wall is 13 m

b) the period of her up-and-down motion is 6.5 s

Explanation:

Given the data in the question;

wavelength λ = 26 m

velocity v = 4.0 m/s

a) How far from the wall is she?

Now, The first antinode is formed at a distance λ/2 from the wall, since the separation distance between the person and wall is;

x = λ/2

we substitute

x = 26 m / 2

x = 13 m

Therefore, the distance between her and the wall is 13 m

b) What is the period of her up-and-down motion?

we know that the relationship between frequency, wavelength and wave speed is;

v = fλ

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we also know that frequency is expressed as the reciprocal of the time period;

f = 1/T

Hence

1/T = v/λ

solve for T

Tv = λ

T = λ/v

we substitute

T = 26 m / 4 m/s

T = 6.5 s

Therefore, the period of her up-and-down motion is 6.5 s

 

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2 years ago
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