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kompoz [17]
3 years ago
14

Melanie paid $42.50 for 3 adult tickets and 2 student tickets at Theater A. Drew paid $47 for 4 student tickets and 2 adult tick

ets at Theater A. Theater B charges $9 for each adult ticket and $7 for each student ticket.
Which of the following statements is TRUE?

A
The price for each adult ticket is the same at both theaters
B
The price for each student ticket is the same at both theaters.
C
The price of an adult ticket at Theater A is $0.50 less than the price of an adult ticket at Theater B.
D
The price of a student ticket at Theater B is $0.50 less than the price of a student ticket at Theater A.
Mathematics
2 answers:
charle [14.2K]3 years ago
6 0

Answer:

Step-by-step explanation:

¿A qué se llamó feudalismo? ¿Dónde y cuándo se desarrolló?

SIZIF [17.4K]3 years ago
6 0

Answer:C the students were amounting to almost nothing in theater a

Step-by-step explanation:

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3 years ago
See image for question.<br><br>Please show workings and diagrams.​
Komok [63]

Answer:

  • a) 258 km
  • b) 267°
  • c) 87°

Step-by-step explanation:

  • <em>Refer to attached diagram (not to scale).</em>
  • <em>Given details are reflected.</em>

<u>First find the measure of angle Q</u>

  • m∠Q = 36° + (180° - 125°) = 91°

a) <u>Use law of cosines to find x:</u>

  • x = √(160² + 200² - 2160*200*cos 91°) = 258 km (rounded)

<u>Use the law of sines to find the missing angles:</u>

  • 258 / sin 91 = 160 / sin R = 200 / sin P
  • m∠R = arcsin (160 sin 91° / 258) = 38°
  • m∠P = 180° - (91° + 38°) = 51°

b) <u>Bearing P from R:</u>

  • 360° - (55° + 38°) = 267°

c)  <u>Bearing R from P:</u>

  • 36° + 51° = 87°

4 0
3 years ago
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The perimeter of a triangle is 60 feet. one side is 12 feet long. of the two unknown sides, one of them is twice as long as the
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One is 36 the other is 12
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What is 5 didvdied by 5836?
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Here's the answer
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A force of 192 lb is required to hold a spring stretched 3 ft beyond its natural length. How much work W is done in stretching i
taurus [48]

Answer:

The work done in stretching the spring is 8 lb.ft

Step-by-step explanation:

Given;

Applied force, F = 192 lb

extension of the spring, x = 3 ft

Determine the spring constant from the applied force and extension;

k = \frac{F}{x} \\\\k = \frac{192 \ lb}{3 \ ft} \\\\k = 64 \ lb/ft

When the spring is stretched 6 inches beyond its natural length, the work done is calculated as follows;

x = 6 inches = 0.5 ft

W = \frac{1}{2} kx^2\\\\W =  \frac{1}{2} (64 \ lb/ft)(0.5 \ ft)^2\\\\W = 8 \ lb.ft

Therefore, the work done in stretching the spring is 8 lb.ft

8 0
2 years ago
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