Answer:
i dont even know un just add it or some thing just add using a calucalotor
Step-by-step explanation:
Answer:
Step-by-step explanation:
- <em>Refer to attached diagram (not to scale).</em>
- <em>Given details are reflected.</em>
<u>First find the measure of angle Q</u>
- m∠Q = 36° + (180° - 125°) = 91°
a) <u>Use law of cosines to find x:</u>
- x = √(160² + 200² - 2160*200*cos 91°) = 258 km (rounded)
<u>Use the law of sines to find the missing angles:</u>
- 258 / sin 91 = 160 / sin R = 200 / sin P
- m∠R = arcsin (160 sin 91° / 258) = 38°
- m∠P = 180° - (91° + 38°) = 51°
b) <u>Bearing P from R:</u>
- 360° - (55° + 38°) = 267°
c) <u>Bearing R from P:</u>
Here's the answer
0.00085675119
Answer:
The work done in stretching the spring is 8 lb.ft
Step-by-step explanation:
Given;
Applied force, F = 192 lb
extension of the spring, x = 3 ft
Determine the spring constant from the applied force and extension;

When the spring is stretched 6 inches beyond its natural length, the work done is calculated as follows;
x = 6 inches = 0.5 ft

Therefore, the work done in stretching the spring is 8 lb.ft