Switch where the x and y are, then solve for y. f(x) = y. 
x = 3y^2 + 6
x-6 = 3y^2
(x-6)/3 = y^2
f^-1(x) = y = sqrt((x-6)/3)
        
             
        
        
        
Answer:
4y+7
Step-by-step explanation:
(12y² + y – 35)/(3y – 5)
=(3y-5)(4y+7)/(3y-5) (factorization)
=4y + 7
Hope this helped!
 
        
             
        
        
        
Answer:
g'(0) = 0
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Pre-Calculus</u>
<u>Calculus</u>
- Derivatives
- Derivative Notation
- The derivative of a constant is equal to 0
- Derivative Property: ![\frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29) 
- Trig Derivative: ![\frac{d}{dx} [cos(x)] = -sin(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcos%28x%29%5D%20%3D%20-sin%28x%29) 
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 8 - 10cos(x)
x = 0
<u>Step 2: Differentiate</u>
- Differentiate [Trig]:                    g'(x) = 0 - 10[-sin(x)]
- Simplify Derivative:                   g'(x) = 10sin(x)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>:                    g'(0) = 10sin(0)
- Evaluate Trig:                      g'(0) = 10(0)
- Multiply:                               g'(0) = 0
 
        
             
        
        
        
It could be 820 thats rounded to the nearest tenth
if its supposedto be rounded to the nearest hundred its 800
        
             
        
        
        
Hello : 
2x² = 2
x²=1
x²-1=0
(x-1)(x+1) = 0
x-1=0 or x+1=0
x=1 or x= -1...(answer : <span>B. There are two solutions: -1 and 1 )</span>