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Svetach [21]
3 years ago
13

Solve for y. pls help me

Mathematics
1 answer:
lesya [120]3 years ago
7 0

Answer:

y should I slove for 'y'

if there's no Y

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Justin weighs 15 pounds less than Greg weighs. Half of Greg’s weight is 75 pounds less than Justin’s weight. How much does each
Ira Lisetskai [31]

Answer:

Justin weighs 165 pounds.

Greg weighs 180 pounds.

3 0
3 years ago
Read 2 more answers
3/4 times 2 1/2 times 4/5
amm1812
The answer to your problem is 6
5 0
3 years ago
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Can a Scalene triangle be a isosceles triangle?<br><br> A: Always<br> B: Never<br> C: Sometimes
arsen [322]
A scalene triangle can never be an isosceles triangle. How? Well, let's take a look at the definition of a scalene triangle. In short, a scalene triangle is a classification of a triangle that does not have any congruent sides. On the other hand, an isosceles triangle is a triangle in which its legs are both congruent. Therefore, if a scalene triangle has two congruent legs, it wouldn't even be a scalene triangle, but instead it would be an isosceles triangle. Hope this helped!
3 0
3 years ago
Write the equation for the word problem and solve. You bought a magazine for $5 and four erasers. You spent a total of $25. How
nikitadnepr [17]

Answer: each eraser cost 5 dollors                

Step-by-step explanation: Simplifying

25 = 5 + 4e

Solving

25 = 5 + 4e

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Add '-4e' to each side of the equation.

25 + -4e = 5 + 4e + -4e

Combine like terms: 4e + -4e = 0

25 + -4e = 5 + 0

25 + -4e = 5

Add '-25' to each side of the equation.

25 + -25 + -4e = 5 + -25

Combine like terms: 25 + -25 = 0

0 + -4e = 5 + -25

-4e = 5 + -25

Combine like terms: 5 + -25 = -20

-4e = -20

Divide each side by '-4'.

e = 5

Simplifying

e = 5

7 0
3 years ago
Please i have 15 minutes​
TEA [102]

Answer:

x = \dfrac{-\log 7}{\log 7 - \log 2}

Step-by-step explanation:

2^x = 7^{x + 1}

Take the log of both sides.

\log 2^x = \log 7^{x + 1}

Use properties of log.

x \log 2 = (x + 1) \log 7

x \log 2 = x \log 7 + \log 7

x \log 2 - x \log 7 = \log 7

x(\log 2 - \log 7) = \log 7

x = \dfrac{\log 7}{\log 2 - \log 7}

x = \dfrac{\log 7}{-(\log 7 - \log 2)}

x = \dfrac{-\log 7}{\log 7 - \log 2}

3 0
3 years ago
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