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2 years ago

Solve for y. pls help me

Mathematics

1 answer:

lesya [120]2 years ago

7 0

Answer:

y should I slove for 'y'

if there's no Y

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The area of the parallelogram below is square meters?

horsena [70]

Answer:

8 Square meters

Step-by-step explanation:

plus the 6m and 2m this meters is both side , so add that then it'll become 8 Square meters

or multiply the 6m and 2m it'll become 12m

3 0

2 years ago

Which confidence level would produce the widest interval when estimating the mean of a population based on the mean and standard

Dvinal [7]

<h3>Answer: A) 99%</h3>

Explanation:

The larger the confidence level, the wider the confidence interval gets. Choice A provides the largest such confidence level.

It's like trying to catch an elusive fish. The wider the net, the more confident that you are likely to catch the fish. The size of the net can be a sort of measure of the confidence level.

4 0

1 year ago

Read 2 more answers

Solve for x: 7x + 15 = 38

oksano4ka [1.4K]

All you do is move all the terms that don't contain " x " to the right side and solve.

x = $\frac{23}{7}$

Hope that helps, Good luck! (:

8 0

2 years ago

Read 2 more answers

C = 5(f-32) / 9 in form ac + b / c

Lera25 [3.4K]

Answer: I don't know if you wanted me to solve for C or F. But, I Solved for both.

Step-by-step explanation:

<u>Solved for F </u>

f=(9C)/(5)+32

<u>Solved for C</u>

C=(5(f-32))/(9)

3 0

2 years ago

The roof of the Terminal Tower is 709 feet above ground. A window washer dropped a bucket from the edge of the roof. How many se

Masja [62]

Answer:

6.64 seconds

Step-by-step explanation:

Given that:

Distance between roof of the terminal and ground = 709 feet

A bucket was dropped from the roof.

To find:

The time taken by the bucket to hit the ground?

Solution:

Distance traveled, $s$ = 709 feet

Initial velocity of the bucket, $u$ = 0 feet/sec (because initially it was at rest)

Acceleration of the bucket will be equal to acceleration due to gravity i.e.

$g$ or 32.1741 $ft/sec^{2}$

Let the time taken is $t$ seconds.

Formula for distance is given as:

$s = ut+\dfrac{1}{2}at^2$

Putting all the values:

$709 = 0 (t) + \dfrac{1}{2}(32.1741) t^2\\\Rightarrow 1418 = 32.1741 t^2\\\Rightarrow t^2 = 44.07\\\Rightarrow t \approx \bold{6.64\ sec}$

6 0

2 years ago