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3 years ago

7

a regular sheet of letter (printing) paper measrues 8.5 inches by 11 inches. you want to cut out squares from each corner that i

t may be folded up to produce an open - top box. What are the dimensions of the square cut outs that will result in a box of maximum volume

1 answer:

Juliette [100K]3 years ago

5 0

Answer:

The dimensions of the square, that will result in a box of maximum volume is a square with side length of approximately 1.585 inches

Step-by-step explanation:

The given dimension of the steel sheet are;

The width = 8.5 inches

The length = 11 inches

Let 'x' represent the side length of the squares cut out, we have;

The length of the box formed, l = 11 - 2·x

The width of the box formed, w = 8.5 - 2·x

The height of the box, h = x

The volume of the box, V = (11 - 2·x) × (8.5 - 2·x) × (x) = 4·x³ - 39·x² + 93.5·x

The maximum or minimum volume is found from dV/dx = 0 at max. or min.

dV/dx = d(4·x³ - 39·x² + 93.5·x)/dx = 12·x² - 78·x + 93.5 = 0

Which gives;

x = (78 ± √((-78)² - 4×12×93.5))/(2 ×12)

x = 4.915 or 1.585

When x = 4.915, V = 4 × 4.915³ - 39 × 4.915² + 93.5 × 4.915 = -7.65

When x = 1.585, V = 4 × 1.585³ - 39 × 1.585² + 93.5 × 1.585 = 66.15

Therefore, the local maximum occurs at x ≈ 1.585

Therefore, the dimensions of the square, 'x' that will result in a box of maximum volume is x ≈ 1.585 inches.

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Step-by-step explanation:

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See attachment for graph

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Required

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<em>See attachment for graph</em>

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