The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
<h3>Ratio of the areas of similar figures </h3>
From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>
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The two figures are similar
From one of the theorems for similar polygons, we have that
If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²
Let the base length of the first figure be ,m = 14 mm
and the base length of the second figure be, n = 7 mm
∴ The ratio of their areas will be



= 4:1
Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1
Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446
The equivalent fractions are 3/4 & 12/16 hope this helps!!
1360/200
13.6/2
6.8
It is a finite decimal, but if you want repeating, there are zeroes that follow, like so:
6.8000000000000 . . . (and on to infinity)
QR =12 because you set up a proportion 21/14=x/8 then cross multiply and get 14x=168 then you divide and get 12