The answer for apex users are:
All of the radii of a circle are congruent
CPCTC
SSS triangle congruence postulate
Answer:
a) 4 - ![vt - d = \frac{1}{2} at^{2}](https://tex.z-dn.net/?f=vt%20-%20d%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20at%5E%7B2%7D)
b) 1 - ![2(vt - d) = at^{2}](https://tex.z-dn.net/?f=2%28vt%20-%20d%29%20%3D%20at%5E%7B2%7D)
c) 6 - ![\frac{2(vt - d)}{t^{2}} = a](https://tex.z-dn.net/?f=%5Cfrac%7B2%28vt%20-%20d%29%7D%7Bt%5E%7B2%7D%7D%20%3D%20a)
Step-by-step explanation:
It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.
We start with:
![d = vt - \frac{1}{2} at^{2}](https://tex.z-dn.net/?f=d%20%3D%20vt%20-%20%5Cfrac%7B1%7D%7B2%7D%20at%5E%7B2%7D)
We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):
![vt - d = \frac{1}{2} at^{2}](https://tex.z-dn.net/?f=vt%20-%20d%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20at%5E%7B2%7D)
Then we multiply each side by 2 to get rid of the 1/2, answer #1:
![2(vt - d) = at^{2}](https://tex.z-dn.net/?f=2%28vt%20-%20d%29%20%3D%20at%5E%7B2%7D)
Finally, we divide each side by t^2 to isolate a (answer #6):
![\frac{2(vt - d)}{t^{2}} = a](https://tex.z-dn.net/?f=%5Cfrac%7B2%28vt%20-%20d%29%7D%7Bt%5E%7B2%7D%7D%20%3D%20a)
Answer:
-2x-2
Step-by-step explanation:
this is the right answer