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ad-work [718]
3 years ago
8

Expand and simplify: 3x(2x-3)^2 - (x+4)

Mathematics
1 answer:
Crazy boy [7]3 years ago
7 0
3x(2x-3)^2 - (x+4)=\\
3x(4x^2-12x+9)-x-4=\\
12x^3-36x^2+27x-x-4=\\
12x^3-36x^2+26x-4
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12 pls. Dis is due tomorrow I need helppp
givi [52]
Multiplying positive numbers always comes out positive, no matter how many there are.  So you can forget about the positive ones.

Every two negative numbers in a multiplication produce a positive.
Another way to say that is:  If the number of negative ones is EVEN,
the answer is positive, and if it's ODD, the answer is negative.

That monster product of eight numbers in problem #12 will be negative,
because there are an odd amount of negative factors in it.
7 0
2 years ago
HELPPPPPPPP I am taking it now
Elena-2011 [213]

Answer:

I'm pretty sure the answer is -a²b and 5a²b

Step-by-step explanation:

8 0
3 years ago
Ill give brainlist
Mariana [72]

The missing step 2 should be;

The quantity of the sum of thirty six plus two divided by 0.5 − 14.8 ÷ 8

The missing step 6 would be that; 76 - 1.85

<h3>How to Solve Mathematical Order of Operations?</h3>

We want to know the steps to solving the expression the quantity of the sum of six squared plus two divided by the absolute value of negative 0.5 − 14.8 ÷ 8

This can be expressed as;

6² + 2 ÷ |-0.5| - 14.8 ÷ 8

Thus, the next step which is step 2 should be;

The quantity of the sum of thirty six plus two divided by 0.5 − 14.8 ÷ 8

The missing step 6 would be that;

76 - 1.85

Read more about Order of Operations at; brainly.com/question/27529825

#SPJ1

7 0
1 year ago
HELPP AND. D IS 10 it got cut out
Inga [223]

Answer: 2

Step-by-step explanation:

2

7 0
2 years ago
Read 2 more answers
Use your understanding of the unit circle and trigonometric functions to find the values requested.
vfiekz [6]

Answer:

a) For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

b) From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

Part b

From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

6 0
2 years ago
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